simple java question

[Fahad]

b=((1|2)^3)&5
acording to java cert book ans b =0
according to calculator b=1
does any one know why
ur answers will be highly apreciated

 

[Ann]

If I compile it and run it I get b=0.

 

[Alex Kizub]

1|2=3
3^3=0
0&5=0
Yuo have bad calculator then.

 

[Gary Labowitz]

b=((1|2)^3)&5
acording to java cert book ans b =0
according to calculator b=1
does any one know why
ur answers will be highly apreciated

To see where you might be going wrong, take it one step at a time.
What results did you get with "calculator" for
1 | 2
(1|2)^3
((1|2)^3) & 5

I get 0, of course.

 

[Joona I Palaste]

b=((1|2)^3)&5
acording to java cert book ans b =0
according to calculator b=1
does any one know why
ur answers will be highly apreciated

What kind of calculator are you using? Let's do it by hand.
1|2 == 3
3^3 == 0
0&5 == 0

--
/-- Joona Palaste ([email protected]) ------------- Finland --------\
\-------------------------------------------------------- rules! --------/
"As a boy, I often dreamed of being a baseball, but now we must go forward, not
backward, upward, not forward, and always whirling, whirling towards freedom!"
- Kang

 

[Peter Kirk]

b=((1|2)^3)&5
acording to java cert book ans b =0
according to calculator b=1
does any one know why
ur answers will be highly apreciated

I am wondering if the ^ symbol is confusing here?

In java it is "exclusive or". Maybe your calculator keyboard has a symbol
which looks like this and means "exponent/to-the-power-of" ?

(just a guess).

Peter

 

[Alex Hunsley]

b=((1|2)^3)&5
acording to java cert book ans b =0
according to calculator b=1
does any one know why
ur answers will be highly apreciated

Try using full stops, capital letters, full words and not hideous
abbreviations like "ur".

 

[Peter Ashford]

I am wondering if the ^ symbol is confusing here?

In java it is "exclusive or". Maybe your calculator keyboard has a symbol
which looks like this and means "exponent/to-the-power-of" ?

(just a guess).

Peter

That was my guess, and to verify I ran the calculation through my
calculator using ^ as "to the power of" and the result was 1, so I think
you've got it right.

 

[Joona I Palaste]

That was my guess, and to verify I ran the calculation through my
calculator using ^ as "to the power of" and the result was 1, so I think
you've got it right.

Let's see now, one step at a time.
1|2 == 3 (binary 11)
3 to the power of 3 == 27 (binary 11011)
27&5 == 1 (in binary: 11011 & 101 == 1)

So this is most likely the right explanation.

--
/-- Joona Palaste ([email protected]) ------------- Finland --------\
\-------------------------------------------------------- rules! --------/
"Outside of a dog, a book is a man's best friend. Inside a dog, it's too dark
to read anyway."
- Groucho Marx