Template speccialization question

[Alfonso Morra]

I have a function template declared as ff:

template <class T1, class T2> size_t find( const T1& col, const T2&
val, const ColFindEnum& dir ) ;


I wanted to specialize it for string,long as ff:

template<> //string, long specialization
size_t find( const std::string& col, long& val, const ColFindEnum& dir )


However, I get a compiler error:
error C2912: explicit specialization; 'size_t A::find(const std::string
&,long &,const Table::ColFindEnum &)' is not a specialization of a
function template

Is it not possible to have a function template that has both template
arguments and arguments with "known types"?

 

[Rob Williscroft]

Alfonso Morra wrote in infra.bt.com in comp.lang.c++:

I have a function template declared as ff:

template <class T1, class T2> size_t find( const T1& col, const T2&
val, const ColFindEnum& dir ) ;


I wanted to specialize it for string,long as ff:

template<> //string, long specialization
size_t find( const std::string& col, long& val, const ColFindEnum& dir
)

Try making it ..., long const &val, ...
.........................^^^^^

long & can't be used to deduce a valid T2 as its declared T2 const &.

However, I get a compiler error:
error C2912: explicit specialization; 'size_t A::find(const std::string
&,long &,const Table::ColFindEnum &)' is not a specialization of a
function template

Is it not possible to have a function template that has both template
arguments and arguments with "known types"?

Partial specializations are illegal, explicit specializations, like you
tried above, are legal.

HTH.

Rob.