Thought you could do this?

[Tomás]

#include <string>

class blah
{
public:

using namespace std;

string k;

};

int main()
{
blah j;
}


Why not?


-Tomás

 

[Victor Bazarov]

#include <string>

class blah
{
public:

using namespace std;

string k;

};

int main()
{
blah j;
}


Why not?

Because the 'using' _directive_ shall not appear inside class scope.
See Standard, subclause 7.3.4 Using directive.

V

 

[Tomás]

Victor Bazarov posted:

Because the 'using' _directive_ shall not appear inside class scope.
See Standard, subclause 7.3.4 Using directive.

V

So I there's the necessity to write the "std", as in:

#include <string>

class blah
{
public:

std::string k;

};


I'm writing code that takes a load of names from a particular namespace,
and so it would be handy to do what I originally intended.

-Tomás

 

[Ben Pope]

Victor Bazarov posted:


So I there's the necessity to write the "std", as in:

#include <string>

class blah
{
public:

std::string k;

};


I'm writing code that takes a load of names from a particular namespace,
and so it would be handy to do what I originally intended.

If it's in a header file, fully qualify everything.

If it's in a source file, just take the directive outside of class scope.

Ben Pope

 

[benben]

I'm writing code that takes a load of names from a particular namespace,

and so it would be handy to do what I originally intended.

-Tomás

Use typedef:

class A
{
private: typedef std::string string;

string a;

// ...
};

Regards,
Ben

 

[Tomás]

benben posted:

Use typedef:

class A
{
private: typedef std::string string;

string a;

// ...
};

Regards,
Ben

: )

-Tomás