# What's up with Time.local ?

P

#### Peter Bailey

I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.

irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^

I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;

irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007

Thanks,
Peter

E

#### Eric Hodel

I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing
with the
Time.local object. I've proven that I can denote which budget
period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.

irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^

I don't get the error when I specify the following date. It doesn't
seem
to like the month of September. (-;

If you put a 0 in front of a number you are specifying an octal
number instead of a decimal number. Octal is base 8, so there is no
such thing as an octal number including a digit greater than 7:

t = Time.local 2007, 011, 011, 00, 00

Time.local 2007, 9, 9, 0, 0

M

#### Morton Goldberg

I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing
with the
Time.local object. I've proven that I can denote which budget
period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.

irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^

I don't get the error when I specify the following date. It doesn't
seem
to like the month of September. (-;

irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007

In Ruby starting an integer with a leading zero designates that it is
in octal notation. The non-negative octal integers start 00, 01, ...,
07, 010, 011, .... There is no 09.

Bottom line: drop the leading zeros.

Regards, Morton

J

#### Jos Backus

I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.

irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)

Numeric literals starting with `0' are interpreted as octal numbers. Try
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^

I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;

irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007

That's because there is no `9' in the base-8 number system, just like there is
no `A' in the regular base-10 number system (but there is in the base-16

Hth,

A

I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.

irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^

The problem is the leading zero. Time.local(2007, 9, 9, 0, 0) works
fine.

Number literals with a zero at the beginning are interpreted as octal
numbers. Since octal numbers only use digits 0..7, 9 is rejected (as
would be 8).

HTH,

P

#### Peter Bailey

The problem is the leading zero. Time.local(2007, 9, 9, 0, 0) works
fine.

Number literals with a zero at the beginning are interpreted as octal
numbers. Since octal numbers only use digits 0..7, 9 is rejected (as
would be 8).

HTH,