XSL: Looping over non xml set

[Tjerk Wolterink]

Hello,

I want to create m elements in this form:

<element index="n"/>

Where n = 1 2 .. m

Can is do this with an xsl:for loop??
And if so how

For example for m = 4

<xsl:variable name="m" select="4"/>
<xsl:for-each select="1 to m">
<element index="{position()}"/>
</foreach>

Output:

<element index="1"/>
<element index="2"/>
<element index="3"/>
<element index="4"/>

Is this possible with xslt 1.0 ?

 

[Joris Gillis]

Hello,

I want to create m elements in this form:

<element index="n"/>

Where n = 1 2 .. m

Can is do this with an xsl:for loop??
And if so how

For example for m = 4

<xsl:variable name="m" select="4"/>
<xsl:for-each select="1 to m">
<element index="{position()}"/>
</foreach>

Output:

<element index="1"/>
<element index="2"/>
<element index="3"/>
<element index="4"/>

Is this possible with xslt 1.0 ?

That's only possible in version 2.0
In XSLT 1.0, you must use a named attribute approach:

<xsl:call-template name="loop">
<xsl:with-param name="count">4</xsl:with-param>
</xsl:call-template>

<xsl:template name="loop">
<xslaram name="count"/>
<xslaram name="iteration">1</xslaram>
<element index="{$iteration}"/>

<xsl:if test="$iteration &lt; $count">
<xsl:call-template name="loop">
<xsl:with-param name="count" select="$count"/>
<xsl:with-param name="iteration" select="$iteration +1"/>
</xsl:call-template>
</xsl:if>

</xsl:template>

regards,

 

[Tjerk Wolterink]

That's only possible in version 2.0
In XSLT 1.0, you must use a named attribute approach:

<xsl:call-template name="loop">
<xsl:with-param name="count">4</xsl:with-param>
</xsl:call-template>

<xsl:template name="loop">
<xslaram name="count"/>
<xslaram name="iteration">1</xslaram>
<element index="{$iteration}"/>

<xsl:if test="$iteration &lt; $count">
<xsl:call-template name="loop">
<xsl:with-param name="count" select="$count"/>
<xsl:with-param name="iteration" select="$iteration +1"/>
</xsl:call-template>
</xsl:if>

</xsl:template>

regards,

that's a smart solution!

 

[David Carlisle]

That's only possible in version 2.0
In XSLT 1.0, you must use a named attribute approach:

Or so long as you know your soource document has enough nodes,

<xsl:for-each select="(//node())[position() &lt;=$m]">
<element index="{position()}"/>
</foreach>

David