array of arrays: searching for wisdom ...

[Alythh]

hi people,
I've some troubles trying to access an array of arrays:
while using the format:

for $i ( 0 .. $#AoA ) {
$row = $AoA[$i];
for $j ( 0 .. $#{$row} ) {
print "element $i $j is $row->[$j]\n";
}
}

surely works, I was wandering if there is a way to scan @AoA for its
$i-th row, and returning it as @i_row, without rebuilding it (by
pushing one-by-one $row->[$j], as in previous example):
it is both an efficiency worry, and a styilistic one: that code is
awful!

Thanks for your help

Alessandro Magni

 

[Tore Aursand]

for $i ( 0 .. $#AoA ) {
$row = $AoA[$i];
for $j ( 0 .. $#{$row} ) {
print "element $i $j is $row->[$j]\n";
}
}

surely works, I was wandering if there is a way to scan @AoA for its
$i-th row, and returning it as @i_row, without rebuilding it (by
pushing one-by-one $row->[$j], as in previous example):
it is both an efficiency worry, and a styilistic one: that code is
awful!

Access it directly (and dereference at the same time);

my $i = 0;
my @i_row = @{$AoA[$i]};

 

[Brian McCauley]

hi people,
I've some troubles trying to access an array of arrays:
while using the format:

for $i ( 0 .. $#AoA ) {
$row = $AoA[$i];
for $j ( 0 .. $#{$row} ) {
print "element $i $j is $row->[$j]\n";
}
}

You should always declare all variables as lexically scoped in the
smallest applicable scope unless you have a reason to do otherwise.

surely works, I was wandering if there is a way to scan @AoA for its
$i-th row, and returning it as @i_row, without rebuilding it (by
pushing one-by-one $row->[$j], as in previous example):

There is no push in the previous example.

The whole of the array referenced by the ARRAYref $row can be addressed
as @$row.