binary string to integer?

[Daqian Yang]

Hi,

string s = "1001";

we I convert s to an integer? thanks.

 

[Christophe Vanfleteren]

Hi,

string s = "1001";

we I convert s to an integer? thanks.

This kind of beginners question is better suited for comp.lang.java.help.

But to answer your question, you can use the Integer.parseInt(String)
method.

 

[Chris McMahan]

Hi,

string s = "1001";

we I convert s to an integer? thanks.

//Try this to get a static int
static int number = Integer.parseInt(s);


//or this for non-static
int number = Integer.getInteger(s).intValue();


You can look at the Javadoc for Integer to get information on these methods

http://java.sun.com/j2se/1.4.1/docs/api/java/lang/Integer.html

- Chris

 

[Christophe Vanfleteren]

//Try this to get a static int
static int number = Integer.parseInt(s);

//or this for non-static
int number = Integer.getInteger(s).intValue();

Excuse me? What difference does it make wether the variable you're assigning
the result to is static or not?

In both cases, you're calling a static method of the Integer class. The only
difference is that the second version returns an Integer (which you're
converting right back to an int), while the first returns the int
immediately.

So unless you actually need an Integer, use the first version.

 

[BarryNL]

Hi,

string s = "1001";

we I convert s to an integer? thanks.

int value = Integer.parseInt(s, 2); // 2 for binary

 

[Daqian Yang]

sorry, the question may not be clear.

Let's say:

String s = "1001";

now I want an integer which is 9 which is 1001 based 2.

 

[Christophe Vanfleteren]

sorry, the question may not be clear.

Let's say:

String s = "1001";

now I want an integer which is 9 which is 1001 based 2.

Have you tried Barry's answer?

int value = Integer.parseInt("1001", 2);  // 2 for binary

will do just fine.

 

[Chris McMahan]

That's what happens when I respond in a hurry.

- Chris

 

[xinyer]

That is helpful for newbies like me...

Thank you Chris !!