can I compare 2 vectors by using ==?

[kathy]

I want to compare 2 vectors to see if all element are equal or not:

std::vector <int> v1;
std::vector <int> v2;

v1.push_back(1);
v1.push_back(2);
v1.push_back(3);

v2.push_back(1);
v2.push_back(2);
v2.push_back(2);

if(v1 == v2)
{
// means every item in v1 is equal to every item in v2
}
else
{

}

 

[Victor Bazarov]

I want to compare 2 vectors to see if all element are equal or not:

Why ask when you can simply try?

V

 

[panxiangming]

vector<int> is can.
but if the data type is you define ,you must overload operation ==.

 

[hde]

Run this and you shall see....... >:-}

#include <iostream>
#include <iomanip>
#include <vector>
using namespace std;

int main() {
vector<int> x;
vector<int> y;

x.push_back(1);
x.push_back(2);
x.push_back(3);
x.push_back(4);

y.push_back(1);
y.push_back(2);
y.push_back(3);
y.push_back(4);

if (x == y)
cout << "x == y" << endl;
else
cout << "x != y" << endl;


x.push_back(4);

if (x == y)
cout << "x == y" << endl;
else
cout << "x != y" << endl;

vector<string>a;
vector<string>b;

a.push_back("Foo");
a.push_back("Bar");
a.push_back("Baz");
a.push_back("Quxx");
a.push_back("Quxxx");

b.push_back("Foo");
b.push_back("Bar");
b.push_back("Baz");
b.push_back("Quxx");
b.push_back("Quxxx");

if (a == b)
cout << "a == b" << endl;
else
cout << "a != b" << endl;

b.push_back("Blah");
if (a == b)
cout << "a == b" << endl;
else
cout << "a != b" << endl;

return 0;
}

 

[Daniel T.]

I want to compare 2 vectors to see if all element are equal or not:

std::vector <int> v1;
std::vector <int> v2;

v1.push_back(1);
v1.push_back(2);
v1.push_back(3);

v2.push_back(1);
v2.push_back(2);
v2.push_back(2);

if(v1 == v2)
{
// means every item in v1 is equal to every item in v2
}
else
{

}

For future reference: <http://www.sgi.com/tech/stl/>

op== tests two vectors for equality. IE the two vectors have the same
size and running "std::equal" over both ranges returns true.

 

[Daniel T.]

Why ask when you can simply try?

Kathy is doing the right thing. Simply trying it isn't good enough. Just
because it works on her compiler doesn't mean the standard guarantees it.