cannot remove multiple spaces

[Tom Cloyd]

I'm baffled by this strange outcome - I cannot reduce multiple spaces
from a text file. This isn't just a regex problem, somehow. I'm failing
to grasp something essential, but don't know what it is. All help
appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and
both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick, but
doesn't

data = open( 'h2t-in2.txt', 'r' ) { |f| ( f.readlines( data )).to_s }

conv.each do |i|
data.gsub!( i[0], i[1] )
end
data.squeeze(' ') # <= putting this here was sheer desperations, but
even THIS fails

open( "h2t-out.txt", "w" ) { |f| f.write( data ) }

end

%w(rubygems ruby-debug readline strscan logger fileutils).each{ |lib|
require lib }

main

=== input file ===

<h1>Library catalog listing </h1>x

<h3>Library catalog listing </h3>x

<h2>Library catalog listing </h2>x

p(subtitle). A complete listing of all material in the Library


=== output file ===


h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

==============

The "x"s in the input file are to show that while the end tags are being
removed the space before them is NOT.

t.

--

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
<< (e-mail address removed) >> (email)
<< TomCloyd.com >> (website)
<< sleightmind.wordpress.com >> (mental health weblog)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 

[Tom Cloyd]

I'm baffled by this strange outcome - I cannot reduce multiple spaces
from a text file. This isn't just a regex problem, somehow. I'm
failing to grasp something essential, but don't know what it is. All
help appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and
both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick, but
doesn't

Ouch. THIS - [ / +/, ' ' ], substituted for [ " +", ' ' ] above fixes
it. I'm going blind, obviously.

t.

data = open( 'h2t-in2.txt', 'r' ) { |f| ( f.readlines( data )).to_s }

conv.each do |i|
data.gsub!( i[0], i[1] )
end
data.squeeze(' ') # <= putting this here was sheer desperations, but
even THIS fails

open( "h2t-out.txt", "w" ) { |f| f.write( data ) }

end

%w(rubygems ruby-debug readline strscan logger fileutils).each{ |lib|
require lib }

main

=== input file ===

<h1>Library catalog listing </h1>x

<h3>Library catalog listing </h3>x

<h2>Library catalog listing </h2>x

p(subtitle). A complete listing of all material in the Library


=== output file ===


h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

==============

The "x"s in the input file are to show that while the end tags are
being removed the space before them is NOT.

t.

--

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
<< (e-mail address removed) >> (email)
<< TomCloyd.com >> (website)
<< sleightmind.wordpress.com >> (mental health weblog)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 

[David A. Black]

Hi --

I'm baffled by this strange outcome - I cannot reduce multiple spaces from
a text file. This isn't just a regex problem, somehow. I'm failing to grasp
something essential, but don't know what it is. All help appreciated, as
usual!

Here is a demo of my problem, in which I try two different ways, and both
fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [ /<\/h\d>/,
'' ],
[ " +", ' ' ]] # <= this last array element should do the trick, but
doesn't

Ouch. THIS - [ / +/, ' ' ], substituted for [ " +", ' ' ] above fixes it. I'm
going blind, obviously.

Just for fun, here's another way to write the method:

def main
data = File.read("tom.txt")
data.gsub!(/<(h[1-6])>/, "\\1. ")
data.gsub!(/<\/h\d>/, "")
data.squeeze!(' ')

open("tom.out", "w") {|f| f.write(data) }

end

I think that does the same thing. Tweak to taste


David

--
David A. Black / Ruby Power and Light, LLC
Ruby/Rails consulting & training: http://www.rubypal.com
Coming in 2009: The Well-Grounded Rubyist (http://manning.com/black2)

http://www.wishsight.com => Independent, social wishlist management!

 

[Craig Demyanovich]

[Note: parts of this message were removed to make it a legal post.]

See comments below.

I'm baffled by this strange outcome - I cannot reduce multiple spaces from
a text file. This isn't just a regex problem, somehow. I'm failing to grasp
something essential, but don't know what it is. All help appreciated, as
usual!

Here is a demo of my problem, in which I try two different ways, and both
fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [ /<\/h\d>/,
'' ],
[ " +", ' ' ]] # <= this last array element should do the trick, but
doesn't

The last element means replace occurrences of a space followed by a plus
with an empty string. I assume that you were trying to write a regular
expression, which would make your last array [/ +/, ''].

data = open( 'h2t-in2.txt', 'r' ) { |f| ( f.readlines( data )).to_s }

conv.each do |i|
data.gsub!( i[0], i[1] )
end
data.squeeze(' ') # <= putting this here was sheer desperations, but even
THIS fails

This does nothing because String#squeeze returns a new string that you don't
capture. Instead of using the array above, you could do

data = data.squeeze(' ')

open( "h2t-out.txt", "w" ) { |f| f.write( data ) }

end

%w(rubygems ruby-debug readline strscan logger fileutils).each{ |lib|
require lib }

main

Hope that helps.

Regards,
Craig

 

[Tom Cloyd]

Hi --

I'm baffled by this strange outcome - I cannot reduce multiple
spaces from a text file. This isn't just a regex problem, somehow.
I'm failing to grasp something essential, but don't know what it is.
All help appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and
both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick,
but doesn't

Ouch. THIS - [ / +/, ' ' ], substituted for [ " +", ' ' ] above fixes
it. I'm going blind, obviously.

Just for fun, here's another way to write the method:

def main
data = File.read("tom.txt")
data.gsub!(/<(h[1-6])>/, "\\1. ")
data.gsub!(/<\/h\d>/, "")
data.squeeze!(' ')

open("tom.out", "w") {|f| f.write(data) }

end

I think that does the same thing. Tweak to taste


David

That's beautifully economical, and reveals a far better grasp of regex
than I was able to attain last night. However, I'm having trouble with
this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet
found anything that might shed light on this magic. How does it retain
the 'h' and whatever digit follows it? It looks somehow like "\\" ==
retain matched alpha, and the "1" does the same for matched digits, but
I really haven't a clue. Can you elucidate just a bit?

Thanks!

Tom

--

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
<< (e-mail address removed) >> (email)
<< TomCloyd.com >> (website)
<< sleightmind.wordpress.com >> (mental health weblog)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 

[David A. Black]

Hi --

Hi --

Tom Cloyd wrote:
I'm baffled by this strange outcome - I cannot reduce multiple spaces
from a text file. This isn't just a regex problem, somehow. I'm failing
to grasp something essential, but don't know what it is. All help
appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and both
fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick, but
doesn't
Ouch. THIS - [ / +/, ' ' ], substituted for [ " +", ' ' ] above fixes it.
I'm going blind, obviously.

Just for fun, here's another way to write the method:

def main
data = File.read("tom.txt")
data.gsub!(/<(h[1-6])>/, "\\1. ")
data.gsub!(/<\/h\d>/, "")
data.squeeze!(' ')

open("tom.out", "w") {|f| f.write(data) }

end

I think that does the same thing. Tweak to taste


David

That's beautifully economical, and reveals a far better grasp of regex than I
was able to attain last night. However, I'm having trouble with this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet found
anything that might shed light on this magic. How does it retain the 'h' and
whatever digit follows it? It looks somehow like "\\" == retain matched
alpha, and the "1" does the same for matched digits, but I really haven't a
clue. Can you elucidate just a bit?

The \\1, \\2, etc. in the replacement string are pegged to the
parenthetical captures. "\\1. " means: the first capture (which is h
plus a digit), a period, and a space.

They work in single-quoted strings too, but there they're just \1, \2,
etc. There's some explanation in the ri docs for String#gsub.


David

--
David A. Black / Ruby Power and Light, LLC
Ruby/Rails consulting & training: http://www.rubypal.com
Coming in 2009: The Well-Grounded Rubyist (http://manning.com/black2)

http://www.wishsight.com => Independent, social wishlist management!

 

[badboy]

Hi --

Tom Cloyd wrote:
I'm baffled by this strange outcome - I cannot reduce multiple
spaces from a text file. This isn't just a regex problem, somehow.
I'm failing to grasp something essential, but don't know what it is.
All help appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and
both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick,
but doesn't
Ouch. THIS - [ / +/, ' ' ], substituted for [ " +", ' ' ] above fixes
it. I'm going blind, obviously.

Just for fun, here's another way to write the method:

def main
data = File.read("tom.txt")
data.gsub!(/<(h[1-6])>/, "\\1. ")
data.gsub!(/<\/h\d>/, "")
data.squeeze!(' ')

open("tom.out", "w") {|f| f.write(data) }

end

I think that does the same thing. Tweak to taste


David

That's beautifully economical, and reveals a far better grasp of regex
than I was able to attain last night. However, I'm having trouble with
this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet
found anything that might shed light on this magic. How does it retain
the 'h' and whatever digit follows it? It looks somehow like "\\" ==
retain matched alpha, and the "1" does the same for matched digits, but
I really haven't a clue. Can you elucidate just a bit?

Thanks!

Tom

ah...regex! it's easy if you know them =D
the (...) in the Regex defines a group.
this group now includes the 'h' followed by one of the numbers 1,2,3,4,5
or 6
in the second parameter \1 (double slash because of
double-quotes/escaping now is assgined to the matched pattern /h[1-6]/
that's it, nothing magic anymore

 

[Robert Klemme]

That's beautifully economical, and reveals a far better grasp of regex
than I was able to attain last night. However, I'm having trouble with
this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet
found anything that might shed light on this magic. How does it retain
the 'h' and whatever digit follows it? It looks somehow like "\\" ==
retain matched alpha, and the "1" does the same for matched digits, but
I really haven't a clue. Can you elucidate just a bit?

The keyword is "capturing groups". Brackets in the regexp denote groups
of characters which can be referenced later via their numeric index as
you have seen. You can even use them for matching repetitions

/(fo+)\1/ =~ s # will match "fofo", "foofoo", "fooofooo" etc.

Cheers

robert

 

[William James]

I'm baffled by this strange outcome - I cannot reduce multiple spaces
from a text file. This isn't just a regex problem, somehow. I'm
failing to grasp something essential, but don't know what it is. All
help appreciated, as usual!

Here is a demo of my problem, in which I try two different ways, and
both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick,
but doesn't

data = open( 'h2t-in2.txt', 'r' ) { |f| ( f.readlines( data )).to_s
}
conv.each do |i|
data.gsub!( i[0], i[1] )
end
data.squeeze(' ') # <= putting this here was sheer desperations,
but even THIS fails

open( "h2t-out.txt", "w" ) { |f| f.write( data ) }

end

%w(rubygems ruby-debug readline strscan logger fileutils).each{ |lib|
require lib }

main

=== input file ===

<h1>Library catalog listing </h1>x

<h3>Library catalog listing </h3>x

<h2>Library catalog listing </h2>x

p(subtitle). A complete listing of all material in the Library


=== output file ===


h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

==============

The "x"s in the input file are to show that while the end tags are
being removed the space before them is NOT.

t.

puts IO.readlines("data2").map{|line|
line.sub( /<(h\d)>/, '\1. ' ).sub( /<\/h\d>/, "").
squeeze " " }

--- output ---

h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

 

[William James]

I'm baffled by this strange outcome - I cannot reduce multiple
spaces from a text file. This isn't just a regex problem, somehow.
I'm failing to grasp something essential, but don't know what it
is. All help appreciated, as usual!

Here is a demo of my problem, in which I try two different ways,
and both fail:

=== code ===
# h2t.rb

def main
# conversion table spec
conv = [
[ '<h1>', 'h1. ' ], [ '<h2>', 'h2. ' ], [ '<h3>', 'h3. ' ],
[ '<h4>', 'h4. ' ], [ '<h5>', 'h5. ' ], [ '<h6>', 'h6. ' ], [
/<\/h\d>/, '' ],
[ " +", ' ' ]] # <= this last array element should do the trick,
but doesn't

data = open( 'h2t-in2.txt', 'r' ) { |f| ( f.readlines( data
)).to_s }
conv.each do |i|
data.gsub!( i[0], i[1] )
end
data.squeeze(' ') # <= putting this here was sheer desperations,
but even THIS fails

open( "h2t-out.txt", "w" ) { |f| f.write( data ) }

end

%w(rubygems ruby-debug readline strscan logger fileutils).each{
|lib| require lib }

main

=== input file ===

<h1>Library catalog listing </h1>x

<h3>Library catalog listing </h3>x

<h2>Library catalog listing </h2>x

p(subtitle). A complete listing of all material in the Library


=== output file ===


h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

==============

The "x"s in the input file are to show that while the end tags are
being removed the space before them is NOT.

t.

puts IO.readlines("data2").map{|line|
line.sub( /<(h\d)>/, '\1. ' ).sub( /<\/h\d>/, "").
squeeze " " }

--- output ---

h1. Library catalog listing x

h3. Library catalog listing x

h2. Library catalog listing x

p(subtitle). A complete listing of all material in the Library

puts IO.read("data2").gsub( /<(h\d)>/, '\1. ' ).gsub( /<\/h\d>/, "").
squeeze " "

 

[Tom Cloyd]

That's beautifully economical, and reveals a far better grasp of
regex than I was able to attain last night. However, I'm having
trouble with this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet
found anything that might shed light on this magic. How does it
retain the 'h' and whatever digit follows it? It looks somehow like
"\\" == retain matched alpha, and the "1" does the same for matched
digits, but I really haven't a clue. Can you elucidate just a bit?

The keyword is "capturing groups". Brackets in the regexp denote
groups of characters which can be referenced later via their numeric
index as you have seen. You can even use them for matching repetitions

/(fo+)\1/ =~ s # will match "fofo", "foofoo", "fooofooo" etc.

Cheers

robert

David, badboy, Robert - thats to you all for the very clear
explanations. I really couldn't find info. about this (yet). It IS
clear, once the explanation's in had. I have to say that regex's
becoming rather fun, now that I'm getting a little control of it.

I continue to be amazed at the generosity of this list in helping the
real amateurs here move things along. We get that AND we get to listen
in on all sorts of amazing and mysterious discussions of higher order
magic. Pretty cool.

t.

--

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
<< (e-mail address removed) >> (email)
<< TomCloyd.com >> (website)
<< sleightmind.wordpress.com >> (mental health weblog)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 

[Tom Cloyd]

That's beautifully economical, and reveals a far better grasp of
regex than I was able to attain last night. However, I'm having
trouble with this line:

data.gsub!(/<(h[1-6])>/, "\\1. ")

It certain works, but I don't grasp the "\\1. " part. I haven't yet
found anything that might shed light on this magic. How does it
retain the 'h' and whatever digit follows it? It looks somehow like
"\\" == retain matched alpha, and the "1" does the same for matched
digits, but I really haven't a clue. Can you elucidate just a bit?

The keyword is "capturing groups". Brackets in the regexp denote
groups of characters which can be referenced later via their numeric
index as you have seen. You can even use them for matching repetitions

/(fo+)\1/ =~ s # will match "fofo", "foofoo", "fooofooo" etc.

Cheers

robert

I should have added this - as it was puzzling me and I just now "got it"
(and no one mentioned it) - for those who might be following along or
will come after: the "\1" business isn't regex. That's why I could find
nothing about it in my regex sources! It's a String#gsub() convention,
and is documented there.

OK...all darkness is vanquished. For now. (!) ~t.

--

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
<< (e-mail address removed) >> (email)
<< TomCloyd.com >> (website)
<< sleightmind.wordpress.com >> (mental health weblog)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 

[MOUBAMBA Laury karin]

how to unsubscribe to this email list ?=0A=0A=0A=0A=0A_____________________=
___________=0ADe : Tom Cloyd <[email protected]>=0A=C3=80 : ruby-talk ML=
<[email protected]>=0AEnvoy=C3=A9 le : Samedi, 7 F=C3=A9vrier 2009, =
22h48mn 08s=0AObjet=C2=A0: Re: cannot remove multiple space> nuts!=0A=0ARob=
ert Klemme wrote:=0A> On 07.02.2009 21:50, Tom Cloyd wrote:=0A>> That's bea=
utifully economical, and reveals a far better grasp of regex than I was abl=
e to attain last night. However, I'm having trouble with this line:=0A>> =
=0A>> data.gsub!(/<(h[1-6])>/, "\\1. ")=0A>> =0A>> It certain works, but I =
don't grasp the "\\1. " part. I haven't yet found anything that might shed =
light on this magic. How does it retain the 'h' and whatever digit follows =
it? It looks somehow like "\\" =3D=3D retain matched alpha, and the "1" doe=
s the same for matched digits, but I really haven't a clue. Can you elucida=
te just a bit?=0A> =0A> The keyword is "capturing groups".=C2=A0 Brackets i=
n the regexp denote groups of characters which can be referenced later via =
their numeric index as you have seen.=C2=A0 You can even use them for match=
ing repetitions=0A> =0A> /(fo+)\1/ =3D~ s # will match "fofo", "foofoo", "f=
ooofooo" etc.=0A> =0A> Cheers=0A> =0A>=C2=A0 =C2=A0 robert=0A> =0A> =0ADavi=
d, badboy, Robert - thats to you all for the very clear explanations. I rea=
lly couldn't find info. about this (yet). It IS clear, once the explanation=
's in had. I have to say that regex's becoming rather fun, now that I'm get=
ting a little control of it.=0A=0AI continue to be amazed at the generosity=
of this list in helping the real amateurs here move things along. We get t=
hat AND we get to listen in on all sorts of amazing and mysterious discussi=
ons of higher order magic. Pretty cool.=0A=0At.=0A=0A-- =0A~~~~~~~~~~~~~~~~=
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=0ATom Cloyd, MS MA, LMHC - Privat=
e practice Psychotherapist=0ABellingham, Washington, U.S.A: (360) 920-1226=
=0A<< (e-mail address removed) >> (email)=0A<< TomCloyd.com >> (website) << sleightm=
ind.wordpress.com >> (mental health weblog)=0A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=
~~~~~~~~~~~~~~~~~~~~~~~~~~~~=0A=0A=0A ________________________________=
__________________________________________________________________=0ANe ple=
urez pas si votre Webmail ferme ! R=C3=A9cup=C3=A9rez votre historique sur =
Yahoo! Mail ! http://fr.docs.yahoo.com/mail/transfert_mails.html

 

[Robert Klemme]

I have to say that regex's
becoming rather fun, now that I'm getting a little control of it.

If you like to dig deeper into the matter, I can recommend
http://oreilly.com/catalog/9780596528126/index.html

I covers functionality, different regexp dialects and performance
considerations thoroughly. Might be a bit difficult to read if you do
not have a full CS background but IMHO Jeff Friedl manages to keep
language theory at a minimum without scarifying precision.

And one more particular Ruby hint: method String#[] is capable of
working with regular expression arguments, so you can do

# fetch the whole match
ip = input[/\d{1,3}(\.\d{1,3}){3}/]

# fetch group 1
name = input[/name=(\S+)/, 1]

Cheers

robert

 

[Jesús Gabriel y Galán]

If you like to dig deeper into the matter, I can recommend
http://oreilly.com/catalog/9780596528126/index.html

I covers functionality, different regexp dialects and performance
considerations thoroughly. Might be a bit difficult to read if you do not
have a full CS background but IMHO Jeff Friedl manages to keep language
theory at a minimum without scarifying precision.

If you want an introductory tutorials about regular expressions you
can check here:
http://www.regular-expressions.info

Jesus.

 

[Tom Cloyd]

If you want an introductory tutorials about regular expressions you
can check here:
http://www.regular-expressions.info

Jesus.

Robert, Jesus,
Thanks to you both. Great stuff. I'll be digging into it tonight.

t.

--

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Tom Cloyd, MS MA, LMHC - Private practice Psychotherapist
Bellingham, Washington, U.S.A: (360) 920-1226
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<< sleightmind.wordpress.com >> (mental health weblog)
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