cast int into a string

[Gary Wessle]

Hi

how can I do this

map<string, int> mp;
int a = 8;

string s = "r_" + reinterpret_cast<string> (a);
mp++;

so that I have r_8 as the key and its number of occurrences as value.

thanks

 

[tragomaskhalos]

Hi

how can I do this

map<string, int> mp;
int a = 8;

string s = "r_" + reinterpret_cast<string> (a);
mp++;

so that I have r_8 as the key and its number of occurrences as value.

That's never going to work - you need to read up on reinterpret_cast.
The answer is here:
http://www.parashift.com/c++-faq-lite/misc-technical-issues.html#faq-39.1

 

[Noah Roberts]

Hi

how can I do this

map<string, int> mp;
int a = 8;

string s = "r_" + reinterpret_cast<string> (a);
mp++;

so that I have r_8 as the key and its number of occurrences as value.

Boost has a lexical_cast "operator" that I believe does what you want.

 

[Gary Wessle]

Hi

how can I do this

map<string, int> mp;
int a = 8;

string s = "r_" + reinterpret_cast<string> (a);
mp++;

so that I have r_8 as the key and its number of occurrences as value.

Boost has a lexical_cast "operator" that I believe does what you want.

thanks, that was easy
#include "boost/lexical_cast.hpp"
using boost::lexical_cast;

int x = 4;
string s = "I am " + lexical_cast<string> (x) + "years old".

(http://www.boost.org/)