Dictionary from a list

[iu2]

Hi all,

I need to create a dictionary out of a list.

Given the list [1, 2, 3, 4, 5, 6]

I need the dictionary: {1:2, 3:4, 5:6}

I'll appreciate your help
Thanks
iu2

 

[Diez B. Roggisch]

Hi all,

I need to create a dictionary out of a list.

Given the list [1, 2, 3, 4, 5, 6]

I need the dictionary: {1:2, 3:4, 5:6}

dict(zip(l[::2], l[1::2]))

Diez

 

[iu2]

Hi all,

I need to create a dictionary out of a list.

Given the list [1, 2, 3, 4, 5, 6]

I need the dictionary: {1:2, 3:4, 5:6}

dict(zip(l[::2], l[1::2]))

Diez

Wow, this is cool!

thanks
iu2

 

[Jan Kaliszewski]

Hi all,

I need to create a dictionary out of a list.

Given the list [1, 2, 3, 4, 5, 6]

I need the dictionary: {1:2, 3:4, 5:6}

dict(zip(l[::2], l[1::2]))

Or (for long lists, when memory becomes expensive):

dict(li[i:i+2] for i in xrange(0, len(li), 2))

Or probably better:

from itertools import islice, izip
dict(izip(islice(li, 0, None, 2), islice(li, 1, None, 2)))

Cheers,
*j

 

[Jan Kaliszewski]

Or probably better:

from itertools import islice, izip
dict(izip(islice(li, 0, None, 2), islice(li, 1, None, 2)))

Or similarly, perhaps more readable:

iterator = iter(li)
dict((iterator.next(), iterator.next()) for i in xrange(len(li)/2))

 

[Peter Otten]

Or similarly, perhaps more readable:

iterator = iter(li)
dict((iterator.next(), iterator.next()) for i in xrange(len(li)/2))

I just can't stop posting this one:

from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

I really tried, but yours drove me over the edge.

Peter

 

[Steven D'Aprano]

I just can't stop posting this one:

from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

I really tried, but yours drove me over the edge.

If you want something to drive you over the edge:

alist = [1, 2, 3, 4, 5, 6]
dict(apply(zip, map(lambda n: map(lambda t: t[1], filter(lambda t:

((not (t[0]%2)) == 1) == n, enumerate(alist))), range(1, -1, -1))))
{1: 2, 3: 4, 5: 6}


Enjoy

 

[Peter Otten]

I just can't stop posting this one:

from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

I really tried, but yours drove me over the edge.

If you want something to drive you over the edge:

I meant that figuratively...

alist = [1, 2, 3, 4, 5, 6]
dict(apply(zip, map(lambda n: map(lambda t: t[1], filter(lambda t:

((not (t[0]%2)) == 1) == n, enumerate(alist))), range(1, -1, -1))))
{1: 2, 3: 4, 5: 6}
....originally.

Enjoy

Not

 

[Tim Chase]

it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

<devo>Zip(it). Zip(it) good.</devo>

it's-3:00am-and-i-seriously-need-to-sleep'ly yers...

-tkc

 

[iu2]

Or similarly, perhaps more readable:

     iterator = iter(li)
     dict((iterator.next(), iterator.next()) for i in xrange(len(li)/2))

I just can't stop posting this one:

from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

I really tried, but yours drove me over the edge.

Peter

Nice.
(but looks like stepping towards the dark side ...

I also liked this one:
iterator = iter(li)
dict((iterator.next(), iterator.next()) for i in xrange(len(li)/2))

which inspired me to do something quite similar:

a=range(1, 11)

a [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
dict([[a.pop(0), a.pop(0)] for i in range(len(a)/2)])

{1: 2, 3: 4, 9: 10, 5: 6, 7: 8}


Thanks

 

[EK]

Or similarly, perhaps more readable:

     iterator = iter(li)
     dict((iterator.next(), iterator.next()) for i in xrange(len(li)/2))

I just can't stop posting this one:

from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

I really tried, but yours drove me over the edge.

Peter

dict(zip(*[iter(l)]*2))

 

[Aahz]

from itertools import izip
it =3D iter([1,2,3,4,5,6])
dict(izip(it, it))

{1: 2, 3: 4, 5: 6}

dict(zip(*[iter(l)]*2))

No, that's not a good solution. For starters, it's less readable than
Peter's version. More importantly, it has poor memory use because it
needs to construct both the intermediate tuple and the zip() list.