Does anyone knows what cause an error as below
"Error :
com.ms.security.SecurityExceptionEx[fileTransfer.actionPerformed]: cannot
access "127.0.0.1":1053".
I have done a file transferring program, when i called the client applet
from html file, error has occured.
1. Applets are not allowed to access many system resources, like writing
files. Or we'll be seeing lots of computer hacked and files erased by
applets. Applets are also not allowed to connect to web sites other than the
one the applet is downloaded from.
2. Stop using Microsoft's VM. It's not standard Java, it's full of bugs,
it's full of security risks (there are virus targetting MSJVM). Download a
Java Runtime Environment (JRE) from java.sun.com. See
http://physci.org/jvmclean.jsp on how to remove MSJVM completely.
3. Source code would help people find out the problem and solution.
http://physci.org/codes/sscce.jsp
4. Stating what you're trying to accomplish will help a lot also. The
problem may not be in your code... it could be in the method you used to
solve the case.
5. This group is archived in groups.google.com. Please use a better subject
line like "SecurityExceptionEx in my applet" instead of just "error", which
means nothing. Doing so will help others to find questions already answered
through the use of Google Groups. Likewise you should search Google Groups
first before posting a question.