Extraction Of Attribute value

[AwanJohnie]

I have an xml document as shown (not mine but extracted from an application):

<category defid="468808" name="Global Information Attributes" versionid="6"> <attributeset attid="1" name="Global Information Attributes"> <attribute attid="3" name="Issue_Date" type="-7">2003-09-30T00:00:00</attribute> <attribute attid="4" name="Review_Date" type="-7">2006-10-30T00:00:00</attribute> </attributeset> </category>

I need to write an XSL to extract the values of 10 the Issue_Date (In this case = 2003-09-30T00:00:00) and Review_Date (In this case = 2006-10-30T00:00:00)

I wrote this in my xsl:

<xsl:value-of select="category/attributeset/attribute/@attid=4"/>

It did not give me the desired result. It gave me a value = true.

In addition how can I trim the date to show only "2003-09-30" for example.

Thanks

 

[Berislav Lopac]

<xsl:value-of select="category/attributeset/attribute/@attid=4"/>

IIRC it should be

<xsl:value-of select="category/attributeset/attribute[@attid=4]" />

 

[Joris Gillis]

to trim the date:

<xsl:value-of select="
substring-before(category/attributeset/attribute[@attid=4],'T')
"/>

 

[AwanJohnie]

IIRC it should be

<xsl:value-of select="category/attributeset/attribute[@attid=4]" />

Thanks for your feedback but it did not return any value.

Secondly, how can I trim the date if result is obtained?

 

[Goudvin Emmanuel]

Try

<xsl:value-of select="category/attributeset/attribute[@attid='4']"/>

 

[AwanJohnie]

Try

<xsl:value-of select="category/attributeset/attribute[@attid='4']"/>

AwanJohnie wrote:

THANKS EVERYBODY.
IT WORKED!!!
THE ACTUAL CODES USED.....

<xsl:value-of select="substring-before(category/attributeset/attribute[@attid='3'],'T')"/>