M
maadhuu
CRobot bot;
bot.init();
cout << "Flag";
bot.func(LEFT);
If i run it like this Flag is never printed. If i comment out
bot.func, then Flag is printed as expected. how does this work?? i.e.if
there is an error in some code following some piece of code ,in this case
,bot.func(LEFT),the present line which might be immediately before it need
not be printed....is there some kind of pipelining that is used by gcc??
how does it work??
bot.init();
cout << "Flag";
bot.func(LEFT);
If i run it like this Flag is never printed. If i comment out
bot.func, then Flag is printed as expected. how does this work?? i.e.if
there is an error in some code following some piece of code ,in this case
,bot.func(LEFT),the present line which might be immediately before it need
not be printed....is there some kind of pipelining that is used by gcc??
how does it work??