How can I create a regexp which do that?

[jfbarro]

Hi!

I am a completly newbie to regexp and I would like to find a regular
expression which execute the following search:
"Show me all *Exception* since they are different from EOFException and
SocketException"

I tried [^EOF]Exception&[^Socket]Exception, but it didn't function like
I expected.

Does anyone have any clue?

Thanks in advance

 

[Josef Moellers]

Hi!

I am a completly newbie to regexp and I would like to find a regular
expression which execute the following search:
"Show me all *Exception* since they are different from EOFException and
SocketException"

I tried [^EOF]Exception&[^Socket]Exception, but it didn't function like
I expected.

The angular brackets ([]) describe character classes, you can view them
as character _sets_, not strings, so your pattern would match anything
that had "Exception" *not* being precedded by either E, O, or F (that
would exclude "EOFException"!). Same applies for the other character class.

If you want to match "Exception" as a free standing word, have a look
(perldoc perlre) at the word boundary meta character '\w'.

HTH,

 

[A. Sinan Unur]

(e-mail address removed) wrote in

I am a completly newbie to regexp and I would like to find a regular
expression which execute the following search:
"Show me all *Exception* since they are different from EOFException
and SocketException"

I tried [^EOF]Exception&[^Socket]Exception, but it didn't function
like I expected.

Does anyone have any clue?

You might be able to do something with look-behind assertions, but I
would just spell it out:

#!/usr/bin/perl

use strict;
use warnings;

my %ignore = (
EOFException => 1,
SocketException => 1,
);

my $text = <<TEXT;
EOFException Exception SocketException IOException
ParseException BzztException and more exceptions
TEXT

while ( $text =~ m{ \b(\w+Exception)\b }gx ) {
my $exception = $1;
unless ( $ignore{$exception} ) {
print "$exception\n";
}
}

Sinan

 

[Tassilo v. Parseval]

Also sprach Josef Moellers:

Hi!

I am a completly newbie to regexp and I would like to find a regular
expression which execute the following search:
"Show me all *Exception* since they are different from EOFException and
SocketException"

I tried [^EOF]Exception&[^Socket]Exception, but it didn't function like
I expected.

The angular brackets ([]) describe character classes, you can view them
as character _sets_, not strings, so your pattern would match anything
that had "Exception" *not* being precedded by either E, O, or F (that
would exclude "EOFException"!). Same applies for the other character class.

If you want to match "Exception" as a free standing word, have a look
(perldoc perlre) at the word boundary meta character '\w'.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
ITYM '\b'.

Tassilo

 

[jfbarro]

Thanks to everybody!!

You guys were very nice!

 

[Josef Moellers]

Also sprach Josef Moellers:

Hi!

I am a completly newbie to regexp and I would like to find a regular
expression which execute the following search:
"Show me all *Exception* since they are different from EOFException and
SocketException"

I tried [^EOF]Exception&[^Socket]Exception, but it didn't function like
I expected.

The angular brackets ([]) describe character classes, you can view them
as character _sets_, not strings, so your pattern would match anything
that had "Exception" *not* being precedded by either E, O, or F (that
would exclude "EOFException"!). Same applies for the other character class.

If you want to match "Exception" as a free standing word, have a look
(perldoc perlre) at the word boundary meta character '\w'.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
ITYM '\b'.

Sorry, yes. That should teach me not to write responses between two
important tasks which both keep me occupied.