how to get file name of the running .py file

[Jason Jiang]

Hi,

How to get the name of the running .py file like the macro _FILE_ in C?

Thanks.
Jason

 

[Larry Bates]

Hi,

How to get the name of the running .py file like the macro _FILE_ in C?

Thanks.
Jason

import os
import sys
print sys.argv[0]

or if you just want the script and not the full path

print os.path.basename(sys.argv[0])

-Larry Bates

 

[Simon Forman]

Hi,

How to get the name of the running .py file like the macro _FILE_ in C?

Thanks.
Jason

import os
import sys
print sys.argv[0]

or if you just want the script and not the full path

print os.path.basename(sys.argv[0])

-Larry Bates

Also, check out:
http://groups.google.ca/group/comp.lang.python/browse_frm/thread/712572b3c2f2cb13

Peace,
~Simon

 

[Jason Jiang]

Thank you guys.

Jason

Hi,

How to get the name of the running .py file like the macro _FILE_ in C?

Thanks.
Jason

import os
import sys
print sys.argv[0]

or if you just want the script and not the full path

print os.path.basename(sys.argv[0])

-Larry Bates

Also, check out:
http://groups.google.ca/group/comp.lang.python/browse_frm/thread/712572b3c2f2cb13

Peace,
~Simon

 

[Bill Pursell]

Hi,

How to get the name of the running .py file like the macro _FILE_ in C?

There are many ways--IMO the easiest is with __file__:
[tmp]$ cat foo.py
#!/usr/bin/env python

print "The name of the file is:%s"%__file__
[tmp]$ ./foo.py
The name of the file is:./foo.py

 

[Fredrik Lundh]

import os
import sys
print sys.argv[0]

or if you just want the script and not the full path

print os.path.basename(sys.argv[0])

except that __FILE__ is the name of the current source file, not the
name of the main program.

the global name __file__ is a better choice; when definied, it points to
the file from which the current module was loaded (this might be a byte
code file or a shared library).

also see:

http://pyref.infogami.com/__file__

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