How to use EOF in C

[Kelsey Bjarnason]

Kelsey Bjarnason wrote:

Notice the other half of the expression?

Grr. Damn this being human thing sucks.

Anyway, regardless the code
is broken since if nch is not less than max, then additional input is
simply discarded.


An '\0' by itself is not a string.

Pass it to strlen, it'll work. Pass the results of whatever you've got
instead, it'll scream and die - if you're lucky.

 

[Richard Heathfield]

Flash Gordon said:

The standard even provides methods of expressing these things Malcolm
acknowledges as different.

char *sausages = NULL; /* No string */
char *sausages == ""; /* Empty string */

/* ITYM syntax error */

 

[Keith Thompson]

Pass it to strlen, it'll work.

strlen('\0') invokes undefined behavior.

I know that's not what you meant. If you pass the address of a
character with value '\0' to strlen(), it will return 0.

 

[Flash Gordon]

Richard Heathfield wrote, On 12/07/07 21:10:

Flash Gordon said:


/* ITYM syntax error */

s/==/=/

 

[Malcolm McLean]

Richard Heathfield wrote, On 12/07/07 21:10:

s/==/=/

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

 

[Ben Pfaff]

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

char *confusing_sausage = &O-0-0-0-0-0-0-0; /* empty string */

 

[Richard Bos]

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

# Constraints
# 1 The operand of the unary & operator shall be either a function
# designator, the result of a [] or unary * operator, or an lvalue
# that designates an object that is not a bit-field and is not
# declared with the register storage-class specifier.

A literal 0 is not any of those, so &0 violates this constraint. Did you
perhaps mean "0" (or even &"0")?

Richard

 

[Keith Thompson]

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

# Constraints
# 1 The operand of the unary & operator shall be either a function
# designator, the result of a [] or unary * operator, or an lvalue
# that designates an object that is not a bit-field and is not
# declared with the register storage-class specifier.

A literal 0 is not any of those, so &0 violates this constraint. Did you
perhaps mean "0" (or even &"0")?

Get a better font, or copy-and-paste the code and try to compile it.
The initializer for 'sausage' is '&O', not '&0' (the letter, not the
digit); 'O' was declared three lines earlier as an object of type
char, initialized to zero.

 

[Kelsey Bjarnason]

strlen('\0') invokes undefined behavior.

True.

I know that's not what you meant. If you pass the address of a
character with value '\0' to strlen(), it will return 0.

In the context used. '\0' "works". In the general case, it doesn't, for
hopefully obvious reasons.

 

[Malcolm McLean]

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

# Constraints
# 1 The operand of the unary & operator shall be either a function
# designator, the result of a [] or unary * operator, or an lvalue
# that designates an object that is not a bit-field and is not
# declared with the register storage-class specifier.

A literal 0 is not any of those, so &0 violates this constraint. Did you
perhaps mean "0" (or even &"0")?

Get a better font, or copy-and-paste the code and try to compile it.
The initializer for 'sausage' is '&O', not '&0' (the letter, not the
digit); 'O' was declared three lines earlier as an object of type
char, initialized to zero.

It was a charred sausage.

 

[Richard Bos]

char O=0; /* sausage */

char *sausages = 0-0-0-0-0-0-0; /* no string */
char *sausage = &O; /* empty string */

# Constraints
# 1 The operand of the unary & operator shall be either a function
# designator, the result of a [] or unary * operator, or an lvalue
# that designates an object that is not a bit-field and is not
# declared with the register storage-class specifier.

A literal 0 is not any of those, so &0 violates this constraint. Did you
perhaps mean "0" (or even &"0")?

Get a better font, or copy-and-paste the code and try to compile it.
The initializer for 'sausage' is '&O', not '&0' (the letter, not the
digit); 'O' was declared three lines earlier as an object of type
char, initialized to zero.

*Hangs head in shame*

It was a charred sausage.

*Groans*

Richard