How to use *input[] as argument

[kjells_]

How can I call a function which takes an argument like this

void func(char *inout[]);

This works okay:
char *pOutPut[500];
for(int i = 0; i < 10; i++)
{
pOutPut = (char*) malloc(33);
}
func(pOutPut);

But if I don't want to use dynamic memory
char pout[10][33];
func(pout); // Compiler error !

func(char **)pout); // exception!

 

[Flash Gordon]

How can I call a function which takes an argument like this

void func(char *inout[]);

But if I don't want to use dynamic memory
char pout[10][33];
func(pout); // Compiler error !

<snip>

Start off with question 6.18 of the comp.lang.c FAQ at http://c-faq.com/
then look through the rest of section 6.