I need help figuring out how to fix this code.

Discussion in 'Python' started by Nathan Pinno, Jun 28, 2005.

  1. Nathan Pinno

    Nathan Pinno Guest

    Hi all,

    I need help figuring out how to fix my code. I'm using Python 2.2.3, and
    it keeps telling me invalid syntax in the if name == "Nathan" line. Here is
    the code if you need it.

    #This program asks for a password, then asks for the user's name after the
    correct password has been supplied. The computers response will vary,
    # depending on the name inputted.
    print "Program Author: Nathan Pinno"
    print "ID# 2413448"
    print "Program 3 - Loops and IF Conditions"
    password = raw_input("Type in the password, please: ")
    while password != "hello":
    print "Incorrect password!"
    print "Welcome to the second half of the program!"
    name = raw_input("What is your name, please? ")
    if name == "Nathan":
    print "What a great name!"
    elif name == ["Madonna", "Cher"]:
    print "May I have your autograph please!"
    print name,", that's a nice name!"

    What's wrong with the code? How do I fix it, so that it works?

    Nathan Pinno
    Nathan Pinno, Jun 28, 2005
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  2. Hi,
    1) check the spacing before if name == "Nathan":
    2) put a ':' after else


    Philippe C. Martin, Jun 28, 2005
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  3. Nathan Pinno

    Jaime Wyant Guest


    It looks like your indentation is off for the if statement. It should
    be aligned with the "name = raw_input" statement above it.

    Also, elif name == ["Madonna", "Cher"]: will never evaluate to true.
    Assume someone enters "guido" for their name, then you're doing this

    "guido" == ["Madonna", "Cher"]

    A string will never equal a list. Now, a string could be in a list.

    if name in ("Madonna", "Cher"):
    print "Sorry, you can't come in."

    Jaime Wyant, Jun 28, 2005
  4. Make sure that line with name=="Nathan" is not indented. It's hard to
    tell from the code there.

    Also, I'm thinking that this won't work:
    if name == "Nathan":
    print "What a great name!"
    elif name == ["Madonna", "Cher"]:

    because the variable name is a string and not a list. You could try:
    elif name in ["Madonna", "Cher"]:

    =?ISO-8859-1?Q?Gregory_Pi=F1ero?=, Jun 28, 2005
  5. Hi,
    The problem is that you indent the if statement. the if/elif/else
    are part of the outer block, so they do not need indentation.
    name = raw_input("What is your name, plase? ")
    if name == "Nathan" :
    print "What a great name!"
    elif name in ["Madonna","Cher"] : # in better than == here :)
    print "May I have your autograph please!"
    else : # don't forget the ":"
    print name, ", thats a nice name!"


    - harold -
    harold fellermann, Jun 28, 2005
  6. Nathan Pinno

    Devan L Guest

    password = raw_input("Type in the password, please: ")
    while password != "hello":
    print "Incorrect password!"
    Wouldn't this print "Incorrect password" untill the end of time if you
    didn't supply the correct password?
    Devan L, Jun 28, 2005
  7. Nathan Pinno

    Chinook Guest

    At least one problem is further within the "if" >

    Python 2.4.1 (#2, Mar 31 2005, 00:05:10)
    [GCC 3.3 20030304 (Apple Computer, Inc. build 1666)]
    Type "help", "copyright", "credits" or "license" for more information.
    Lee C
    Chinook, Jun 28, 2005
    Hash: SHA1

    I think about all the problems in your code are solved by suggestions
    sent before me, but I have some advice for future situations:

    Especially with more complex problems, larger code blocks using external
    libs, etc, you should, if appropriate, include the Traceback, some
    explanation on the given code(what it should do etc.) and maybe consider
    documenting the code a little with comments and docstrings(try reading
    some code you haven't seen before or in a long time, without any
    commentation. What about debugging it without knowing what the code is
    supposed to do?) Don't be intimidated by this, you just seemed to be new
    with programming with python and thought of sharing this with you. You
    have maybe read something like this before from a book or tutorial(there
    are a couple of good free books for learning python, for example "byte
    of python"), but good commenting and the like are usually appreciated
    only when they're not available:)

    Hope I didn't scare you. Happy tinkering with python!

    Elmo Mäntynen
    Version: GnuPG v1.4.1 (GNU/Linux)
    Comment: Using GnuPG with Thunderbird - http://enigmail.mozdev.org

    -----END PGP SIGNATURE-----
    =?ISO-8859-1?Q?Elmo_M=E4ntynen?=, Jun 29, 2005
  9. Nathan Pinno

    Brian Guest

    Hi Nathan,

    Please see my comments listed below.

    At this point, you need to add the following statement again:
    password = raw_input("Type in the password, please: ")

    Otherwise, it just keeps stating "Incorrect password!" forever without
    giving the user the ability to re-enter another password attemp / try.

    Remove the tab indentions in front of the "if", "elif", and "else"
    statements. This will cause an error in your program. The only time
    that you need to indent is the code following the if statements.

    if name == "Steven":
    print "Then I indent this code here."
    print "This is another coded statement here."

    You're welcome, Nathan!

    Hope this helps (HTH),

    Brian, Jun 29, 2005
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