Missing xmlns attribute while indenting using xalan (JAVA)

[Hyunchan Kim]

To indent xml file, I made an instance of Transformer from Templates using following.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xslt" version="1.0"> <xslutput method="xml" indent="yes" xalan:indent-amount="4"/> <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet>

The transform seems to work fine, most of the cases. But if I call transform above XML as an input, output has only one xmlns attribute like this.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xalan="http://xml.apache.org/xslt"
version="1.0">
<xslutput method="xml" indent="yes" xalan:indent-amount="4"/> <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet>

Following attribute is lost...
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

If I modify "xmlns:xsl" to "mlns:xsl" (delete first character to see what happens), output is correct i.e, root element has two attributes including mlns:xsl="http://www.w3.org/1999/XSL/Transform"

I have read some reference materials to find out what's wrong. But I can't find any problem. As I know so far, <xsl:template match="/"> means root of DOM tree and <xsl:copy-of select="."/> means copy that to target document.

So, I think everything should go fine...

Does anyone know what's wrong?

 

[Martin Honnen]

To indent xml file, I made an instance of Transformer from Templates using following.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xslt" version="1.0"> <xslutput method="xml" indent="yes" xalan:indent-amount="4"/> <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet>

The transform seems to work fine, most of the cases. But if I call transform above XML as an input, output has only one xmlns attribute like this.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xalan="http://xml.apache.org/xslt"
version="1.0">
<xslutput method="xml" indent="yes" xalan:indent-amount="4"/> <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet>

Following attribute is lost...
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

If I modify "xmlns:xsl" to "mlns:xsl" (delete first character to see what happens), output is correct i.e, root element has two attributes including mlns:xsl="http://www.w3.org/1999/XSL/Transform"

I have read some reference materials to find out what's wrong. But I can't find any problem. As I know so far, <xsl:template match="/"> means root of DOM tree and <xsl:copy-of select="."/> means copy that to target document.

So, I think everything should go fine...

Does anyone know what's wrong?

Well, the namespace http://www.w3.org/1999/XSL/Transform has to be declared in every stylesheet but should not be output normally so it is tricky to have it included. I don't have a solution currently, maybe you can find something in the XSL FAQ:
http://www.dpawson.co.uk/xsl/sect2/N5536.html#d5360e1276