default namespace and xmlns=""

Mike Dickens

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hi,
i'm sure this has come up before but havn't managed to find an answer.
if i have the following xslt

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet method="xml" version="1.0" xmlns:ns1="abc" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:eek:utput indent="yes" media-type="text/xml" standalone="yes" version="1.0"/> <xsl:template match="/"> <x> <xsl:element name="y" namespace="abc"> <xsl:apply-templates select="/a"/> </xsl:element> </x> </xsl:template> <xsl:template match="/a"> <z> <xsl:value-of select="b"/> </z> </xsl:template> </xsl:stylesheet>

and apply it to the following xml

<a>
<b>hello</b>
</a>

i get

<?xml version="1.0" standalone="yes"?>
<x xmlns:ns1="abc">
<y xmlns="abc">
<z xmlns="">hello</z>
</y>
</x>

my question is this. is it possible to remove the xmlns="" bit without having to use <ns1:z> in the xslt?

thanks,
mike
 

Marrow (2)

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Hi Mike,
my question is this. is it possible to remove the xmlns="" bit without having to use <ns1:z> in the xslt?

It is not possible to 'remove' namespace declarations placed in the output by the transformation engine. The transformation engine decides, to some degree under your instruction, what namespace declarations are needed. In this case your <z> element is bound to the null namespace (i.e. the namespace URI is "") - the only way to 'removing' that namespace declaration would be to bind the <z> element to a different namespace... which I suspect, but am not sure, is what you are asking... how to bind <z> to the "abc" namespace?

One way to start taking control of your output namespace is to define the default output namespace in your stylesheet, e.g.

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns1="abc" xmlns="abc">

The default namespace for the stylesheet is used as the default namespace for the output.

Having done that, then you only need to specify namespace prefixes (or @namespace-uri on <xsl:element>/<xsl:attribute>) where you want elements/attributes to be bound to a different namespace to the default output namespace.

Another thing that can help you 'control' (to a degree) the output namespace declarations is to use the <xsl:namespace-alias> instruction, for example to declare your prefix 'ns1' (e.g. xmlns:ns1="abc") in the stylesheet and then have that transposed to the default output namespace (e.g. xmlns="abc")
would be to specify that...

<xsl:namespace-alias stylesheet-prefix="ns1" result-prefix="#default"/>

So putting those together, your stylesheet might look like...

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ns1="abc" xmlns="abc">

<xsl:namespace-alias stylesheet-prefix="ns1" result-prefix="#default"/>

<xsl:eek:utput indent="yes" media-type="text/xml" standalone="yes" version="1.0"/> <xsl:template match="/"> <x> <ns1:y> <xsl:apply-templates select="/a"/> </ns1:y> </x> </xsl:template>

<xsl:template match="/a">
<z>
<xsl:value-of select="b"/>
</z>
</xsl:template>
</xsl:stylesheet>

which would give an output of...

<?xml version="1.0" encoding="UTF-16" standalone="yes"?> <x xmlns="abc"> <y> <z>hello</z> </y> </x>

Although then there would be no particular reason to declare the 'ns1' namespace prefix at all nor specify the @namespace-uri attribute on <xsl:element> (come to that, there is no particular reason to use <xsl:element> in this case at all). So your stylesheet really just needs to be...

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="abc">

<xsl:eek:utput method="xml" indent="yes"/>
<xsl:template match="/">
<x>
<y>
<xsl:apply-templates select="/a"/>
</y>
</x>
</xsl:template>

<xsl:template match="/a">
<z>
<xsl:value-of select="b"/>
</z>
</xsl:template>
</xsl:stylesheet>

NB. Really, the only times when you need to use <xsl:element> is where the element name or namespace URI is being defined dynamically, i.e. where either the @name or @namespace-uri attributes contain an AVT (attribute value template).

HTH
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger) http://www.topxml.com/Xselerator
 

David Carlisle

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<?xml version="1.0" standalone="yes"?>
<x xmlns:ns1="abc">
<y xmlns="abc">
<z xmlns="">hello</z>
</y>
</x>

my question is this. is it possible to remove the xmlns="" bit without having to use <ns1:z> in the xslt?

You probbaly want to generate z in the namespace abc which you could do in the xsl by using <z xmlns="abc">

Usuallly you put such a result namespace declaration on your xsl:stylesheet element then it's in scope for the whole stylesheet and would mean you could replace <xsl:element name="y" namespace="abc"> by <y>

and just use <z> to generate z.

If you really want x to be in no-namespace you could do <xsl:element name="x" namespace="">

David
 

Mike Dickens

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yes, that's what i meant, though possible put as have <z> inherit the namespace of it's parent rather bind to "abc" specifically. this is because there are potentially lots of z's...
 

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