Problem in using typedef with c++

A

Abhi Us

Hi
My code is as follows :-
example.h

#include"iostream.h"
using namespace std;
typedef int MYINT;
void sum(MYINT a, MYINT b);

example.cpp
#include"example.h"
void sum(MYINT a, MYINT b)
{
MYINT c;
c=a +b;
cout<<c;
}

example.i
%module example
%{
#include"example.h"
extern void sum(MYINT a, MYINT b);
%}

#include "example.h"
extern void sum(MYINT a,MYINT b);



example.rb

require "example.so"
MYINT a=10;
MYINT b=20;
Example.sum(a,b);

But it is giving me error undefined MYINT when i'm trying to compile
 
N

Nobuyoshi Nakada

Hi,

At Wed, 19 Mar 2008 19:24:46 +0900,
Abhi Us wrote in [ruby-talk:295033]:
example.rb

require "example.so"
MYINT a=10;
MYINT b=20;

Is this file written in Ruby, or in C++?
 
P

Paul Brannan

Hi
My code is as follows :-
example.h

#include"iostream.h"
using namespace std;

Please don't put "using namespace" inside header files. This can cause
conflict with code that includes the header but doesn't expect to get
the namespace.
typedef int MYINT;
void sum(MYINT a, MYINT b);

example.cpp
#include"example.h"
void sum(MYINT a, MYINT b)
{
MYINT c;
c=a +b;
cout<<c;
}

example.i
%module example
%{
#include"example.h"
extern void sum(MYINT a, MYINT b);
%}

#include "example.h"
extern void sum(MYINT a,MYINT b);



example.rb

require "example.so"
MYINT a=10;
MYINT b=20;
Example.sum(a,b);

But it is giving me error undefined MYINT when i'm trying to compile

In Ruby, variables do not have types (all variables are references to
Objects, and the type of the Object is determined dynamicaly). If you
write instead:

a=10
b=20
Example.sum(a,b)

I think it should work.

Note that you don't need to terminate your lines with a semicolon in
Ruby.

Paul
 
A

Abhi Us

Paul said:
Please don't put "using namespace" inside header files. This can cause
conflict with code that includes the header but doesn't expect to get
the namespace.


In Ruby, variables do not have types (all variables are references to
Objects, and the type of the Object is determined dynamicaly). If you
write instead:

a=10
b=20
Example.sum(a,b)

I think it should work.

Note that you don't need to terminate your lines with a semicolon in
Ruby.

Paul


Hi i got ur point that ruby do not have types. Then suppose if i have
user defined data type for e.g

map<int,string> MYmap;
is present in C++ code.How should i create the instances of it in ruby.
Can i write like
m1.insert(1,"amey")
and it will be treated as the map which i have defined..
 
P

Paul Brannan

Hi i got ur point that ruby do not have types. Then suppose if i have
user defined data type for e.g

map<int,string> MYmap;
is present in C++ code.How should i create the instances of it in ruby.
Can i write like
m1.insert(1,"amey")
and it will be treated as the map which i have defined..

You probably want to create a typemap between your map type and ruby's
hash type. You can read about typemaps here:

http://www.swig.org/Doc1.3/Typemaps.html

Paul
 

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