problem with google api / xml

[robin]

hello,

i installed SOAPpy 0.12.0 and pyXML 0.8.4 in order to try out the
google-search example in diveintopython
http://diveintopython.org/soap_web_services/index.html
however, i'v been trying and trying and won't get it to work :-(
whenever i run this code, i get the attached exception...

from SOAPpy import WSDL
WSDLFILE = '/pathtomy/googleapi/GoogleSearch.wsdl'
APIKEY = '....'
_server = WSDL.Proxy(WSDLFILE)

any help would be very much appreciated!
thanks in advance,
robin

Traceback (most recent call last):
File "<stdin>", line 1, in ?
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/SOAPpy/WSDL.py",
line 67, in __init__
self.wsdl = reader.loadFromString(str(wsdlsource))
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/SOAPpy/wstools/WSDLTools.py",
line 47, in loadFromString
return self.loadFromStream(StringIO(data))
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/SOAPpy/wstools/WSDLTools.py",
line 28, in loadFromStream
document = DOM.loadDocument(stream)
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/SOAPpy/wstools/Utility.py",
line 602, in loadDocument
return xml.dom.minidom.parse(data)
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/_xmlplus/dom/minidom.py",
line 1915, in parse
return expatbuilder.parse(file)
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/_xmlplus/dom/expatbuilder.py",
line 930, in parse
result = builder.parseFile(file)
File
"/Library/Frameworks/Python.framework/Versions/2.4/lib/python2.4/site-packages/_xmlplus/dom/expatbuilder.py",
line 207, in parseFile
parser.Parse(buffer, 0)
xml.parsers.expat.ExpatError: not well-formed (invalid token): line 1,
column 0

 

[Mike Kent]

from SOAPpy import WSDL
WSDLFILE = '/pathtomy/googleapi/GoogleSearch.wsdl'
APIKEY = '....'
_server = WSDL.Proxy(WSDLFILE)

Robin, note this part of the URI set in WSDLFILE:
'/pathtomy/googleapi'. Get it? 'path to my google api'. You must set
this part to the actual path where the file 'GoogleSearch.wsdl' is
found. In addition, doesn't APIKEY = '....' look a bit odd to you?
Hmm, what could this mean. APIKEY. Perhaps you need to get an API key
from Google in order to use their search API, and fill it in there?

;-)

 

[robin]

hi kent,

thanks for your reply. in fact it was me who put "pathtomy" into the
path and exchanged my apikey with "...."
i prefer not everyone to know the name of my directories and even less
my apikey. so the problem isn't there :-(
hope to find some other solution....
thanks!!

robin

 

[John Bokma]

hello,

i installed SOAPpy 0.12.0 and pyXML 0.8.4 in order to try out the
google-search example in diveintopython
http://diveintopython.org/soap_web_services/index.html
however, i'v been trying and trying and won't get it to work :-(
whenever i run this code, i get the attached exception...

from SOAPpy import WSDL
WSDLFILE = '/pathtomy/googleapi/GoogleSearch.wsdl'
[...]

ackages/_xmlplus/dom/expatbuilder.py", line 207, in parseFile
parser.Parse(buffer, 0)
xml.parsers.expat.ExpatError: not well-formed (invalid token): line 1,
column 0

Did you check your GoogleSearch.wsdl file? From the error I guess that
something is wrong with the file itself. I Recommend to check it, or
download it again:

http://api.google.com/GoogleSearch.wsdl

No experience with SOAPpy, but with SOAP::Lite (Perl), I can give the uri
to that file (OTOH, hosting it localy might be faster).