Question about binary file reading

[vibgyorbits]

I'm writing a tool to do some binary file comparisons.
I'm opening the file using

fd=open(filename,'rb')

# Need to seek to 0x80 (hex 80th) location

fd.seek(0x80)

# Need to read just 8 bytes and get the result back in hex format.
x=fd.read(8)
print x

This prints out garbage. I would like to know what am i missing here.
Basically, I am trying to read
8 bytes from location 0x80 from a binary file called "filename"

Any tips/inputs are welcome.

thanks!

 

[Chris Rebert]

I'm writing a tool to do some binary file comparisons.
I'm opening the file using

fd=open(filename,'rb')

# Need to seek to 0x80 (hex 80th) location

fd.seek(0x80)

# Need to read just 8 bytes and get the result back in hex format.
x=fd.read(8)
print x

This prints out garbage. I would like to know what am i missing here.

`print x` outputs the raw bytes in the bytestring `x` you just read,
which yes, generally looks like gibberish.
It doesn't magically convert it to hex format. Remember that
bytestrings could just as well contain ASCII in other situations,
which you certainly wouldn't want to see as hex. You'll have to
explicitly/manually do the conversion from bytes->hex.

Cheers,
Chris