Set a variable as in setter

[Kless]

Is there any way to simplify the next code? Because I'm setting a
variable by default of the same way than it's set in the setter.

-------------------
class Foo(object):
def __init__(self, bar):
self._bar = self._change(bar) # !!! as setter

@property
def bar(self):
return self._bar

@bar.setter
def bar(self, bar):
self._bar = self._change(bar) # !!! as in init

def _change(self, text):
return text + 'any change'
-------------------

 

[Mike Kazantsev]

Is there any way to simplify the next code? Because I'm setting a
variable by default of the same way than it's set in the setter.

Guess it's obvious, but why not use "setattr(self, 'bar', bar)" here, in
__init__ - it'll just call defined setter.

@property
def bar(self):
return self._bar

@bar.setter
def bar(self, bar):
self._bar = self._change(bar) # !!! as in init

def _change(self, text):
return text + 'any change'
-------------------

--
Mike Kazantsev // fraggod.net

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[Mike Kazantsev]

Guess it's obvious, but why not use "setattr(self, 'bar', bar)" here, in
__init__ - it'll just call defined setter.

In fact, "self.bar = bar" is even simplier.
Somehow I thought it wouldn't work here, but it does.


--
Mike Kazantsev // fraggod.net

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[Kless]

What's wrong with just doing this?:
        self.bar = bar

Because 'bar' is going to be modified before of be saved.

 

[Kless]

Because 'bar' is going to be modified before of be saved.

Sorry! It works well. The problem was because I was using it from
iPython.

 

[Dave Angel]

Because 'bar' is going to be modified before of be saved.

You can't modify bar, it's immutable (string).

Did you try the suggestion, or just assume it won't work? self.bar will
call your setter method just as well from __init__() as it does outside
the class. So that eliminates the need for a separate _change() method.

class Foo(object):
def __init__(self, bar):
self.bar = bar

@property
def bar(self):
return self._bar

@bar.setter
def bar(self, text):
self._bar = text + "any change"