Sorting a list

[RC]

unsortedList = list(["XYZ","ABC"])

sortedList = unsortedList.sort()
print sortedList


Why this return None?
How do I get return as ["ABC", "XYZ"]?

 

[Steve Holden]

unsortedList = list(["XYZ","ABC"])

sortedList = unsortedList.sort()
print sortedList


Why this return None?
How do I get return as ["ABC", "XYZ"]?

The list's .sort method returns None because it modifies the list
in-place, so after the call it is sorted. So you can either not assign
the list and use unsortedList (whose name now belies its sorted
condition) or you can use

sprtedList = sorted(unsortedList)

since the sorted() function returns a sorted copy of its argument.

regards
Steve

 

[duncan smith]

unsortedList = list(["XYZ","ABC"])

sortedList = unsortedList.sort()
print sortedList


Why this return None?

Because the sort method sorts the list in place (and returns None).

How do I get return as ["ABC", "XYZ"]?

unsortedList = ["XYZ","ABC"]
unsortedList.sort()
unsortedList

['ABC', 'XYZ']

or if you want a distinct sorted list (leaving the original list unchanged)

unsortedList = ["XYZ","ABC"]
sortedList = sorted(unsortedList)
unsortedList ['XYZ', 'ABC']
sortedList ['ABC', 'XYZ']

Duncan