why does this prg does not display "NONE"

[sunny]

int a=10;
switch(a)
{
case '1':
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
defa1ut:
printf("NONE\n");
}

 

[Richard Heathfield]

sunny said:

int a=10;
switch(a)
{
case '1':
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
defa1ut:

Well, duh.

 

[Preben Traerup]

int a=10;
switch(a)
{
case '1':
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
defa1ut:
printf("NONE\n");
}

propably because a does not have value defalut
../Preben

 

[ramasubramanian.rahul]

check the spelling of default ... and dont waste others time with such
hopeless questions

 

[zorigaman]

sunny a écrit :

int a=10;
switch(a)
{
case '1':
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
default:
printf("NONE\n");
}

Because it seems that with the quotes, you're evalutating the character
(ascii code), not the value itself.
Try :

 

[Clever Monkey]

int a=10;
switch(a)
{
case '1':
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
defa1ut:
printf("NONE\n");
}

Why do people continue to post this lame snippet?