1.9.1 regex 6.5 times slower than 1.8.6 in at least one case

M

Michael Brooks

Hello:

In general I've found Ruby 1.9.1 to be 2 times faster than 1.8.6 and
roughly the same speed as Python 2.8 which is great... thanks guys,
great job!

However, in one case, when using a regular expressions (posted here by
someone a long time ago) which I use to determine what numbers in
0..10000 are prime numbers, version 1.9.1 was at least 6.5 times slower
(1.8.6 = 67 secs, 1.9.1 = 457 secs).

The regular express is:

((("1" * self) =~ /^1$|^(11+?)\1+$/) == nil)

which I've used in different versions of my program running either on
its own or as part of an overloading function as follows:

# Add an "is_prime?" method to the built-in numeric class
# which returns true if the number is a prime number.
class Fixnum
def is_prime?
((("1" * self) =~ /^1$|^(11+?)\1+$/) == nil)
end
end

I also have a version of the prime-number calculation program that which
doesn't use the above regex (i.e. it uses a traditional brute force
approach instead) and it runs 2 times faster in 1.9.1. In 1.9.1 the
regex gets exponentially worse as the number being evaluated exceeding
1000.

Does anyone know why the regex in 1.9.1 is so much slower than 1.8.6?

Thank You,

Michael
 
D

Daniel DeLorme

Michael said:
However, in one case, when using a regular expressions (posted here by
someone a long time ago) which I use to determine what numbers in
0..10000 are prime numbers, version 1.9.1 was at least 6.5 times slower
(1.8.6 = 67 secs, 1.9.1 = 457 secs).

The regular express is:

((("1" * self) =~ /^1$|^(11+?)\1+$/) == nil)

As the only guy who would rather use a regex rather than string slicing,
that's disheartening news. One thing you might want to check is your
encoding. If your default encoding is UTF8, some string operations can
be significantly slower:

$ cat p-regex.rb
4000.times do |i|
((("1" * i) =~ /^1$|^(11+?)\1+$/) == nil)
end

$ time 1.8/bin/ruby -KN -v p-regex.rb
ruby 1.8.6 (2008-08-11 patchlevel 287) [i686-linux]
real 0m4.411s
user 0m4.292s
sys 0m0.032s

$ time 1.8/bin/ruby -KU -v p-regex.rb
ruby 1.8.6 (2008-08-11 patchlevel 287) [i686-linux]
real 0m4.480s
user 0m4.320s
sys 0m0.004s

$ time 1.9/bin/ruby -KN -v p-regex.rb
ruby 1.9.1p0 (2009-02-22 revision 22551) [i686-linux]
real 0m8.041s
user 0m7.980s
sys 0m0.020s

$ time 1.9/bin/ruby -KU -v p-regex.rb
ruby 1.9.1p0 (2009-02-22 revision 22551) [i686-linux]
real 0m21.709s
user 0m20.913s
sys 0m0.032s

With ascii encoding, ruby1.9 is still slower than 1.8 but at least not
six times slower.
 
M

Michael Brooks

Daniel said:
Michael said:
However, in one case, when using a regular expressions (posted here by
someone a long time ago) which I use to determine what numbers in
0..10000 are prime numbers, version 1.9.1 was at least 6.5 times slower
(1.8.6 = 67 secs, 1.9.1 = 457 secs).

The regular express is:

((("1" * self) =~ /^1$|^(11+?)\1+$/) == nil)

As the only guy who would rather use a regex rather than string slicing,
that's disheartening news. One thing you might want to check is your
encoding. If your default encoding is UTF8, some string operations can
be significantly slower:

$ cat p-regex.rb
4000.times do |i|
((("1" * i) =~ /^1$|^(11+?)\1+$/) == nil)
end

$ time 1.8/bin/ruby -KN -v p-regex.rb
ruby 1.8.6 (2008-08-11 patchlevel 287) [i686-linux] > real 0m4.411s

$ time 1.8/bin/ruby -KU -v p-regex.rb
ruby 1.8.6 (2008-08-11 patchlevel 287) [i686-linux] > real 0m4.480s

$ time 1.9/bin/ruby -KN -v p-regex.rb
ruby 1.9.1p0 (2009-02-22 revision 22551) [i686-linux] > real 0m8.041s

$ time 1.9/bin/ruby -KU -v p-regex.rb
ruby 1.9.1p0 (2009-02-22 revision 22551) [i686-linux] > real 0m21.709s

With ascii encoding, ruby1.9 is still slower than 1.8 but at least not
six times slower.

Daniel

Hello Daniel:

Interesting, I didn't know about those switches.

I ran my 10000 iteration prime number calc program using ruby 1.9.1 with
no switch then with the two switches you identified:

ruby "fprim v5.rb" > 477.47 seconds
ruby -KN "fprim v5.rb" > 500.89 seconds
ruby -KU "fprim v5.rb" > 1059.04 seconds

Each test was run twice and the lower number from each reported above.
I'm not sure why it's slower than the numbers I first reported.

I'm running Windows XP (which I know is slower than Linux and the
default Windows compiled binaries for 1.9.1 might be having some impact
too) on an unplugged AMD 1.9 GHz based laptop (it runs at about 1.1 GHz
when unplugged) with 2 GB ram. I'm not sure what my default ruby
encoding is but it appears to be a bit faster than the -KN switch.

To put those numbers in perspective, if I run your code on my unplugged
laptop with the -KN switch it takes 37.07 seconds and without any switch
36.85 seconds. If I change your code to use 10000 iterations and run it
with the -KN switch it takes 477.36 seconds and without any switch
500.44 seconds (which is strange because it's a flip of numbers in the
fprim test).

All I can say regarding regex performance and 1.9.1 is OUCH.

Michael
 
B

BIl Kleb

Michael said:
However, in one case, when using a regular expressions (posted here by
someone a long time ago) which I use to determine what numbers in
0..10000 are prime numbers, version 1.9.1 was at least 6.5 times slower
(1.8.6 = 67 secs, 1.9.1 = 457 secs).

I found similar results lately, but the difference was more like a
factor of 12!

RUBY 1.8.6:

$ cd FUN3D
$ find . -name \*_c.\?90 -exec rm {} \;
$ time ruby Ruby/complex_transformations_spike.rb
[...]
real 0m25.221s
user 0m22.292s
sys 0m0.759s

$ ruby -v
ruby 1.8.6 (2008-03-03 patchlevel 114) [universal-darwin9.0]
(as comes with OS X)

RUBY 1.9.1:

$ cd /usr/local/src
$ wget ftp://ftp.ruby-lang.org/pub/ruby/1.9/ruby-1.9.1-p0.tar.gz
$ tar zxf ruby-1.9.1-p0.tar.gz
$ cd ruby-1.9.1-p0
$ ./configure --program-suffix=19 --enable-shared
$ make
$ sudo make install
$ cd -

$ time ruby19 Ruby/complex_transformations_spike.rb
[...]
real 5m18.188s
user 4m54.253s
sys 0m2.866s

$ ruby19 -v
ruby 1.9.1p0 (2009-01-30 revision 21907) [i386-darwin9.6.0]

Regards,
 

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