Convert two char into one int

[Mariano]

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

 

[Kenny McCormack]

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

Continue with:

num[2] = 0;
sscanf(num,"%d",&integ):

 

[Fred Yu]

I have this lines:

char *chr;
int integ;
num[0] = '1';
num[1] = '9';

How I could obtain value 19 in the integ variable????
Hi to all.

integ = atoi(num[0])*10+atoi(num[1]);

 

[Nick Keighley]

"Mariano" <[email protected]>
:8a82a41a-1992-4fa3-9c9b-bc4f6c2b3...@e39g2000hsf.googlegroups.com...

I have this lines:
char *chr;
int integ;
num[0] = '1';
num[1] = '9';
How I could obtain value 19 in the integ variable????
Hi to all.

integ = atoi(num[0])*10+atoi(num[1]);

That's wrong.
num[0] is not a pointer to a string.

and num may not be a valid string, we don't
know if there's a terminating nul character

atoi takes a pointer to a string as an argument.

and has poor error handling