Getting an object's class definition namespace

[Martin Boese]

In a program I module_eval class definitions into a dynamically created
namespace. To run support code later on I need to know the module it was
defined in from an instance of the class.

Is there any _NICE_ way to replace this 'cheat version'? The below also
doesn't work with nested modules.

module X
class A
def my_module
Object::const_get(self.class.name.split('::')[0])
end
end
end

a = X::A.new
a.my_module => X

Thanks!
martin

 

[James Coglan]

[Note: parts of this message were removed to make it a legal post.]

In a program I module_eval class definitions into a dynamically created
namespace. To run support code later on I need to know the module it was
defined in from an instance of the class.

Would Module.nesting work for you?

irb(main):001:0> module X
irb(main):002:1> class A
irb(main):003:2> def nesting
irb(main):004:3> Module.nesting
irb(main):005:3> end
irb(main):006:2> end
irb(main):007:1> end
=> nil
irb(main):008:0> X::A.new.nesting
=> [X::A, X]

 

[Martin Boese]

Would Module.nesting work for you?

Yes! Thanks.