Proxy Authentication using urllib2


A

Andre Bocchini

I'm having some trouble using proxy authentication. I can't figure out
how to authenticate with a Squid proxy. I know for a fact the proxy is
using Basic instead of Digest for the authentication. I can
authenticate just fine using Mozilla. I've done some Google searches,
but the closest piece of code I've is is for HTTPBasicAuthHandler:

# set up authentication info
authinfo = urllib2.HTTPBasicAuthHandler()
authinfo.add_password('realm', 'host', 'username', 'password')
proxy_support = urllib2.ProxyHandler({"http" : "http://ahad-haam:3128"})
# build a new opener that adds authentication and caching FTP handlers
opener = urllib2.build_opener(proxy_support, authinfo,
urllib2.CacheFTPHandler)
# install it
urllib2.install_opener(opener)
f = urllib2.urlopen('http://www.python.org/')

Can anybody point me in the right direction to some more detailed
documentation? I haven't really been able to understand what I found
in the Python Library Reference either.

I thought something like this might work, but is didn't:

proxy_handler = urllib2.ProxyHandler({"http" : "http://myproxy:3128"})
proxy_auth_handler = urllib2.ProxyBasicAuthHandler()
proxy_auth_handler.add_password(None, "myproxy", "myname", "mypass")
opener = urllib2.build_opener(proxy_handler, proxy_auth_handler)
urllib2.install_opener(opener)
f = urllib2.urlopen("http://www.python.org")
data = f.readlines()

I always get a 407 error.

Well, thanks in advance.

-- Andre
 
Ad

Advertisements

J

John J. Lee

Andre Bocchini said:
I'm having some trouble using proxy authentication. I can't figure
out how to authenticate with a Squid proxy. I know for a fact the
proxy is using Basic instead of Digest for the authentication. I can
authenticate just fine using Mozilla. I've done some Google searches,
but the closest piece of code I've is is for HTTPBasicAuthHandler: [...]
proxy_handler = urllib2.ProxyHandler({"http" : "http://myproxy:3128"})
proxy_auth_handler = urllib2.ProxyBasicAuthHandler()
proxy_auth_handler.add_password(None, "myproxy", "myname", "mypass")
opener = urllib2.build_opener(proxy_handler, proxy_auth_handler)
urllib2.install_opener(opener)
f = urllib2.urlopen("http://www.python.org")
data = f.readlines()

Can't see anything wrong with that.

I always get a 407 error.

Are you sure you don't need a realm? Try sniffing what Mozilla and
Python are sending (using eg. ethereal). You *should* get a 407
response, IIRC, but then urllib2 should respond with an appropriate
Proxy-authorization header.

If that helped, please look at the doc patch here

http://www.python.org/sf/798244


test it, and post a comment to say whether or not it worked (and which
examples you tried -- preferably all of them ;).


John
 
Ad

Advertisements

M

Myles

Andre Bocchini said:
I'm having some trouble using proxy authentication. I can't figure out
how to authenticate with a Squid proxy. I know for a fact the proxy is

A piece of code that works through a Squid proxy here - originally
clipped from comp.lang.python - possibly an eff-bot post if my dim
memory serves me correctly.

---- snip ----
import urllib2

proxy_info = {
'user' : 'username',
'pass' : 'password',
'host' : "proxy.name.com",
'port' : 80 # or 8080 or whatever
}

# build a new opener that uses a proxy requiring authorization
proxy_support = urllib2.ProxyHandler({"http" : \
"http://%(user)s:%(pass)[email protected]%(host)s:%(port)d" % proxy_info})
opener = urllib2.build_opener(proxy_support, urllib2.HTTPHandler)

# install it
urllib2.install_opener(opener)

# use it
f = urllib2.urlopen('http://www.python.org/')
print f.headers
print f.read()
---- snip ----

Regards, Myles.
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Top