XSL transformation not finding template

[Kevin Dean]

I'm trying to create an XSL transformation that will strip out development-specific attributes from deployment descriptors and other XML files. I have already successfully done so with web.xml but I'm at a complete loss as to what is wrong with the one below. This is a very abbreviated server-config.wsdd:

<?xml version="1.0" encoding="UTF-8"?>
<deployment xmlns="http://xml.apache.org/axis/wsdd/" xmlns:java="http://xml.apache.org/axis/wsdd/providers/java"> <globalConfiguration> <parameter name="adminPassword" value="admin"/> <parameter name="sendXsiTypes" value="true"/> <parameter name="sendMultiRefs" value="true"/> <parameter name="sendXMLDeclaration" value="true"/> <parameter name="axis.sendMinimizedElements" value="true"/> <requestFlow> <handler type="javarg.apache.axis.handlers.JWSHandler"> <parameter name="scope" value="session"/> </handler> <handler type="javarg.apache.axis.handlers.JWSHandler"> <parameter name="scope" value="request"/> <parameter name="extension" value=".jwr"/> </handler> <handler type="javarg.apache.axis.handlers.SOAPMonitorHandler"/> </requestFlow> <responseFlow> <handler type="javarg.apache.axis.handlers.SOAPMonitorHandler"/> </responseFlow> </globalConfiguration> </deployment>

What I'd like to do is copy the entire file but filter out the global request and response flow elements. To that end, I have created the following XSL:

<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xslutput method="xml" version="1.0" />

<xsl:template match="@*|node">
<xsl:copy>
<xsl:apply-templates select="@*|node" />
</xsl:copy>
</xsl:template>

<xsl:template match="/deployment/globalConfiguration/requestFlow" />

<xsl:template match="/deployment/globalConfiguration/responseFlow" /> </xsl:stylesheet>

Basically, I want the XSL transformation to remove the
/deployment/globalConfiguration/requestFlow and
/deployment/globalConfiguration/responseFlow paths. As I said earlier, I have done this quite successfully in web.xml (stripping out Axis administration servlet) but I'm stumped as to why this wouldn't be working in this instance.

Any help would be most appreciated.

 

[vin sharma]

I'm trying to create an XSL transformation that will strip out development-specific attributes from deployment descriptors and other XML files. I have already successfully done so with web.xml but I'm at a complete loss as to what is wrong with the one below. This is a very abbreviated server-config.wsdd:

<?xml version="1.0" encoding="UTF-8"?>
<deployment xmlns="http://xml.apache.org/axis/wsdd/" xmlns:java="http://xml.apache.org/axis/wsdd/providers/java"> ....

</deployment>

What I'd like to do is copy the entire file but filter out the global request and response flow elements. To that end, I have created the following XSL:

<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xslutput method="xml" version="1.0" /> ....

</xsl:stylesheet>

Basically, I want the XSL transformation to remove the
/deployment/globalConfiguration/requestFlow and
/deployment/globalConfiguration/responseFlow paths. As I said earlier, I have done this quite successfully in web.xml (stripping out Axis administration servlet) but I'm stumped as to why this wouldn't be working in this instance.

Any help would be most appreciated.

Try specifying the source namespace in the stylesheet:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://xml.apache.org/axis/wsdd/" version="1.0">

-vin

 

[Kevin Dean]

No good. I still get the identity transformation back. Here's an even simpler version of the XSL that should return an empty transformation but doesn't:

<?xml version="1.0" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://xml.apache.org/axis/wsdd/" version="1.0"> <xslutput method="xml" version="1.0" />

<xsl:template match="@*|node">
<xsl:copy>
<xsl:apply-templates select="@*|node" />
</xsl:copy>
</xsl:template>

<xsl:template match="/deployment" />
</xsl:stylesheet>

 

[Marrow]

Hi Kevin,

Because the elements you are trying to filter out are bound to the default namespace (i.e. xmlns="http://xml.apache.org/axis/wsdd/" ) in your input XML.

So to match those elements - you need to declare that namespace in your stylesheet with an arbitrary prefix (remember that namespaces are matched by their URI rather than prefix). Then use that arbitrary prefix in your match patterns, e.g.

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ws="http://xml.apache.org/axis/wsdd/"> <xslutput method="xml" version="1.0" />

<xsl:template match="@*|node">
<xsl:copy>
<xsl:apply-templates select="@*|node" />
</xsl:copy>
</xsl:template>

<xsl:template match="ws:requestFlow | ws:responseFlow" />

</xsl:stylesheet>

Hope this helps
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger) http://www.topxml.com/Xselerator

 

[Kevin Dean]

Perfect, thank you.

Hi Kevin,

Because the elements you are trying to filter out are bound to the default namespace (i.e. xmlns="http://xml.apache.org/axis/wsdd/" ) in your input XML.

So to match those elements - you need to declare that namespace in your stylesheet with an arbitrary prefix (remember that namespaces are matched by their URI rather than prefix). Then use that arbitrary prefix in your match patterns, e.g.

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ws="http://xml.apache.org/axis/wsdd/"> <xslutput method="xml" version="1.0" />

<xsl:template match="@*|node">
<xsl:copy>
<xsl:apply-templates select="@*|node" />
</xsl:copy>
</xsl:template>

<xsl:template match="ws:requestFlow | ws:responseFlow" />

</xsl:stylesheet>

Hope this helps
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger) http://www.topxml.com/Xselerator