"10, 20, 30" to [10, 20, 30]

[Daniel Austria]

Sorry,

how can i convert a string like "10, 20, 30" to a list [10, 20, 30]

what i can do is:

s = "10, 20, 30"
tmp = '[' + s + ']'
l = eval(tmp)

but in my opinion this is not a nice solution


daniel

 

[Tech]

Daniel Austria a écrit :

Sorry,

how can i convert a string like "10, 20, 30" to a list [10, 20, 30]

what i can do is:

s = "10, 20, 30"
tmp = '[' + s + ']'
l = eval(tmp)

but in my opinion this is not a nice solution


daniel

If you're sure that there's only ints
l = [int(item) for item in s.split(', ')]

Yannick

 

[John Machin]

Sorry,

how can i convert a string like "10, 20, 30" to a list [10, 20, 30]

what i can do is:

s = "10, 20, 30"
tmp = '[' + s + ']'
l = eval(tmp)

but in my opinion this is not a nice solution

Most people share your opinion. Try this:

| >>> strg = "10, 20, 30"
| >>> [int(x) for x in strg.split(',')]
| [10, 20, 30]

Cheers,
John

 

[Steven D'Aprano]

Sorry,

how can i convert a string like "10, 20, 30" to a list [10, 20, 30]

what i can do is:

s = "10, 20, 30"
tmp = '[' + s + ']'
l = eval(tmp)

but in my opinion this is not a nice solution

It is a dangerous solution if your data is coming from an untrusted source.

s = "10, 20, 30"
L = [x.strip() for x in s.split(',')]
L ['10', '20', '30']
L = [int(x) for x in L]
L

[10, 20, 30]

Or, as a one liner: [int(x.strip()) for x in s.split(',')]

 

[Tim Williams]

Sorry,

how can i convert a string like "10, 20, 30" to a list [10, 20, 30]

what i can do is:

s = "10, 20, 30"
tmp = '[' + s + ']'
l = eval(tmp)

but in my opinion this is not a nice solution

It is a dangerous solution if your data is coming from an untrusted source.

s = "10, 20, 30"
L = [x.strip() for x in s.split(',')]
L ['10', '20', '30']
L = [int(x) for x in L]
L

[10, 20, 30]

Or, as a one liner: [int(x.strip()) for x in s.split(',')]

You don't need the strip()

 

[Fredrik Lundh]

It is a dangerous solution if your data is coming from an untrusted source.

s = "10, 20, 30"
L = [x.strip() for x in s.split(',')]
L ['10', '20', '30']
L = [int(x) for x in L]
L

[10, 20, 30]

Or, as a one liner: [int(x.strip()) for x in s.split(',')]

You don't need the strip()

and the use of a list comprehension is pretty silly to, given that you want
to apply the same *function* to all items, and don't really need to look
it up for every item:

map(int, s.split(','))

</F>

 

[Tim Williams]

and the use of a list comprehension is pretty silly to, given that you want
to apply the same *function* to all items, and don't really need to look
it up for every item:

map(int, s.split(','))

Haha, thanks Frederic, I wondered how long it would take for a reply
from you

"Silly" though ??

Tim