Help !! for typecasting char* to short array

[LinuxGuy]

Hi,
can someone pl. help me to convert character array into short
array.
actually I need in one function. but currently I have input as
character array.

Thanks

 

[Sharad Kala]

Hi,
can someone pl. help me to convert character array into short
array.
actually I need in one function. but currently I have input as
character array.

Can you show your attempt at it ? People here can help you better once they
know what you are trying.

Sharad

 

[Mike Wahler]

Hi,
can someone pl. help me to convert character array into short
array.
actually I need in one function. but currently I have input as
character array.

Your description is rather vague. I'll only guess
that you want to copy the character array's elements
to corresponding elements in the short array.

void func(const char *c, short *s, size_t count)
{
size_t i = 0;

while(i < count++)
s = c;
}

-Mike

 

[Howard]

Your description is rather vague. I'll only guess
that you want to copy the character array's elements
to corresponding elements in the short array.

void func(const char *c, short *s, size_t count)
{
size_t i = 0;

while(i < count++)

Did you mean...

while (i++ < count)

perhaps?


-Howard

 

[Mike Wahler]

Did you mean...

while (i++ < count)

perhaps?

Almost. What I wrote is wrong, of course, should be
something like:

while(i < count)
{
s = c;
++i;
}

Sorry for the error, 'LinuxGuy', and
thanks for pointing it out, Howard.

-Mike

 

[Old Wolf]

Did you mean...

while (i++ < count)

Almost. What I wrote is wrong, of course, should be
something like:

while(i < count)
{
s = c;
++i;
}

It seems there are good reasons to prefer:

std::copy(c, c + count, s);

 

[Mike Wahler]

"Mike Wahler" <[email protected]> wrote:

while(i < count)
{
s = c;
++i;
}

It seems there are good reasons to prefer:

std::copy(c, c + count, s);

Yes, of course. When I first answered, my mind was
more in 'C mode'.

-Mike