how to design an testing example

[qazwsx746]

The content of my program are the following:

#include <stdio.h>
int main(int argc,char *argv[])
{ FILE *fp;
void filecopy(FILE *,FILE *);
if (argc==1)
filecopy(stdin,stdout);
else
while (--argc>0)
if ((fp=fopen(*++argv,"r"))==NULL) {
printf("cat:can't open %s\n",*argv);
return 1;
} else {
filecopy(fp,stdout);
fclose(fp);
}
return 0;
}
void filecopy(FILE *ifp,FILE *ofp)
{int c;
while ((c=getc(ifp))!=EOF)
putc(c,ofp);
}
when I input command lines,for example:cat f:\test\1.cpp (windows xp
is installed in my computer)
the output are :cat f:\test\1.cpp
The angrument which is f:\test\1.cpp donot have work,and output is cat
f:\test\1.cpp
I know the program have no problem.
But I can't run the program corretly?
What should I do?

 

[Subbu]

Hi,

While passing the file name use "\\" insted of "\".

Best Regards,
Subra..

 

[Richard Heathfield]

Subbu said:

Hi,

While passing the file name use "\\" insted of "\".

No. File names might not even /have/ a \ character as part of their name. At
least as far as I'm aware, none of the files on my filesystem does, and
even if the OP's system does, the advice doesn't apply to the OP anyway.
The reason for using \\ instead of \ when you want a \ in astring literal
is nothing to do with files and everything to do with string literals.

 

[Keith Thompson]

The content of my program are the following:

#include <stdio.h>
int main(int argc,char *argv[])
{ FILE *fp;
void filecopy(FILE *,FILE *);
if (argc==1)
filecopy(stdin,stdout);
else
while (--argc>0)
if ((fp=fopen(*++argv,"r"))==NULL) {
printf("cat:can't open %s\n",*argv);
return 1;
} else {
filecopy(fp,stdout);
fclose(fp);
}
return 0;
}
void filecopy(FILE *ifp,FILE *ofp)
{int c;
while ((c=getc(ifp))!=EOF)
putc(c,ofp);
}
when I input command lines,for example:cat f:\test\1.cpp (windows xp
is installed in my computer)
the output are :cat f:\test\1.cpp
The angrument which is f:\test\1.cpp donot have work,and output is cat
f:\test\1.cpp
I know the program have no problem.
But I can't run the program corretly?
What should I do?

While passing the file name use "\\" insted of "\".

Please don't top-post. See the following:

http://www.caliburn.nl/topposting.html
http://www.cpax.org.uk/prg/writings/topposting.php

That's not likely to be the problem. A backslash character is
represented as "\\" in a string literal or character constant in C
source code; the syntax doesn't necessarily apply to whatever provides
a program's command-line arguments. <OT>In particular, it's not
likely to apply on Windows.</OT>

 

[Richard Bos]

The content of my program are the following:

#include <stdio.h>
int main(int argc,char *argv[])
{ FILE *fp;
void filecopy(FILE *,FILE *);
if (argc==1)
filecopy(stdin,stdout);
else
while (--argc>0)
if ((fp=fopen(*++argv,"r"))==NULL) {
printf("cat:can't open %s\n",*argv);
return 1;
} else {
filecopy(fp,stdout);
fclose(fp);
}
return 0;
}
void filecopy(FILE *ifp,FILE *ofp)
{int c;
while ((c=getc(ifp))!=EOF)
putc(c,ofp);
}
when I input command lines,for example:cat f:\test\1.cpp (windows xp
is installed in my computer)
the output are :cat f:\test\1.cpp
The angrument which is f:\test\1.cpp donot have work,and output is cat
f:\test\1.cpp
I know the program have no problem.
But I can't run the program corretly?
What should I do?

Call it correctly. The program is correct. It would be too much to say
that it has no problems, since it is horribly formatted, but it is at
least correct. I can compile it and run it, and it works both with stdin
and with a file I specify. Are you absolutely sure the filename you give
it is correct? Try the same command with type instead of cat, and see if
that does show up.

Richard

 

[Barry Schwarz]

The content of my program are the following:

#include <stdio.h>
int main(int argc,char *argv[])
{ FILE *fp;
void filecopy(FILE *,FILE *);
if (argc==1)
filecopy(stdin,stdout);
else
while (--argc>0)
if ((fp=fopen(*++argv,"r"))==NULL) {
printf("cat:can't open %s\n",*argv);
return 1;
} else {
filecopy(fp,stdout);
fclose(fp);
}
return 0;
}
void filecopy(FILE *ifp,FILE *ofp)
{int c;
while ((c=getc(ifp))!=EOF)
putc(c,ofp);
}
when I input command lines,for example:cat f:\test\1.cpp (windows xp
is installed in my computer)
the output are :cat f:\test\1.cpp

There is no printf statement in your program which will produce this
output. What is the real output from your program?

The angrument which is f:\test\1.cpp donot have work,and output is cat
f:\test\1.cpp
I know the program have no problem.
But I can't run the program corretly?

These two statements are mutually exclusive. If the program had no
problem, it would run correctly.

What should I do?

Remove del for email

 

[Nick Keighley]

The content of my program are the following:

#include <stdio.h>
int main(int argc,char *argv[])
{ FILE *fp;
void filecopy(FILE *,FILE *);
if (argc==1)
filecopy(stdin,stdout);
else
while (--argc>0)
if ((fp=fopen(*++argv,"r"))==NULL) {
printf("cat:can't open %s\n",*argv);
return 1;
} else {
filecopy(fp,stdout);
fclose(fp);
}
return 0;
}
void filecopy(FILE *ifp,FILE *ofp)
{int c;
while ((c=getc(ifp))!=EOF)
putc(c,ofp);
}

I really don't understand what you're saying. Could you state what
input
you gave your program, what output you expected and what output you
expected.

This may be exactly what you intended to do, but it was not clear to
me.

Try formatting it like this:
input: cat f:\test\1.cpp
expected: cat f:\test\1.cpp
actual: ???

when I input command lines,for example:cat f:\test\1.cpp (windows xp
is installed in my computer)
the output are :cat f:\test\1.cpp
The angrument which is f:\test\1.cpp donot have work,and output is cat
f:\test\1.cpp

I can't see which is the expected and which the actual output

I know the program have no problem.

excellent! So you have no problem?