U
user923005
Thank you Ben!
I made a little modification to my program, and now it behaves like
your program.
As I calculated, the chances to get at least one number less than 1000
in 6e6 numbers is: 1-(1-1000/(2^32))^6000000 = 0.7527...
It corresponds very well with the current performance of my program.
Thank you all !
I would like to apologize for the perceived tone of my first post. I
did not intend to offend.
Glad that you got your code to work properly.