Sort by number of characters

[musicman1985]

Hello,
How can I use jQuery to sort a book list by number of characters of each book.
This is my script, the html is to long:

$(() => {
  const comparator = (a, b, direction = 1) =>
    a < b ?
      -direction :
      (a > b ? direction : 0);
  const sortKeys = {
    date: $cell => Date.parse(`1 ${$cell.text()}`),
    alpha: $cell => $.trim(
      $cell.find('span.sort-key').text() + ' ' +
      $cell.text().toUpperCase()
    ),
    numeric($cell) {
      const key = parseFloat(
        $cell
          .text()
          .replace(/^[^\d.]*/, '')
      );
      return isNaN(key) ? 0 : key;
    }
  };

  $('#t-1')
    .find('thead th')
    .slice(1)
    .each((i, element) => {
      $(element).data(
        'keyType',
        element.className.replace(/^sort-/,'')
      );
    })
    .wrapInner($('<a/>').attr('href', '#'))
    .addClass('sort')
    .on('click', (e) => {
      e.preventDefault();

      const $target = $(e.currentTarget);
      const column = $target.index();
      const keyType = $target.data('keyType');
      const sortDirection = $target.hasClass('sorted-asc') ?
        -1 : 1;

      $('#t-1')
        .find('tbody > tr')
        .each((i, element) => {
          $(element).data(
            'sortKey',
            sortKeys[keyType](
              $(element)
                .children('td')
                .eq(column)
            )
          );
        })
        .get()
        .sort((a, b) => comparator(
          $(a).data('sortKey'),
          $(b).data('sortKey'),
          sortDirection
        ))
        .forEach((element) => {
          $(element)
            .parent()
            .append(element);
        });

      $target
        .siblings()
        .addBack()
        .removeClass('sorted-asc sorted-desc')
        .end()
        .end()
        .addClass(
          sortDirection == 1 ?
            'sorted-asc' : 'sorted-desc'
        );
    });
});