That is comic. In the company we were forced to rview
all the C++ code that used "max" since in C++ max
doesn't allow for ifferent arguments in its parameters
since it is a template
Only if you rely automatic template parameter deduction...
int main(void)
{
// Specify the template parameter
printf("%d\n",(int) std::max<double>(6.4,2));
}
Besides, is max(6.4, 7) an integer or a double?
It doesn't really matter in a simple assignment, but it matters with
operator overloading. If I have
foo(int n);
and
foo(double x);
which should I call if the code says
foo(std::max(6.4,7)); // which foo()?
Given that you've added operator/function overloading to C, I'd expect
you to have a grasp on these issues.
Alternatively, just define your own...
namespace jacob_navias_workplace
{
template <typename T, typename U>
const T& max(const T& l, const U& r){
return r > l ? T(r) : l;
}
}
And, if you define a non-const overload you keep have nice syntax like
double x = 3.0, y = 7.0;
// set larger value to zero
max(x,y) = 0.0;
