Popping up the "Open With" dialog window

[Micah]

I know it's possible to use os.startfile() to open/execute a file based on
its extension, but when a file is not recognized, I get a WindowsError with
Errno 1155.

Is there any way (using wxPython) to popup the "Open With" dialog that
appears when trying to open an unrecognized file in Windows Explorer?

Thanks,
Micah

--
=================================
Micah Z. Wedemeyer
Research Scientist I, ELSYS
Georgia Tech Research Institute
Atlanta, GA 30332
678.428.1283
=================================

 

[Cliff Wells]

I know it's possible to use os.startfile() to open/execute a file based on
its extension, but when a file is not recognized, I get a WindowsError with
Errno 1155.

Is there any way (using wxPython) to popup the "Open With" dialog that
appears when trying to open an unrecognized file in Windows Explorer?

No. You'll probably have to look to the native win32all package for
that.

Regards,
Cliff